13.5 N 19 Degrees West of North 9.40 N East7.20 N SouthExamine the Information shown above. What is the net force on the object? 7.41 N, 47.5° above the positive x-axis 5.54 N, 48.1° above the positive x-axis 24.0 N, 18.8° above the negative x-axis 11.9 N, 20.1° below the negative x-axis

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Description: 13.5 N 19 Degrees West of North 9.40 N East7.20 N SouthExamine the Information shown above. What is the net force on the object? 7.41 N, 47.5° above the positive x-axis 5.54 N, 48.1° above the positive x-axis 24.0 N, 18.8° above the negative x-axis 1

Given: Force F1→=13.5 N makes an angle 19° west of north. Force F2→=9.40 N towards east. Force…

Answered: net force

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

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Problem 29P: An object of mass m = 1.00 kg is observed to have an acceleration a with a magnitude of 10.0 m/s2 in...

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13.5 N 19 Degrees West of North

9.40 N East

7.20 N South

Examine the Information shown above. What is the net force on the object?

	7.41 N, 47.5° above the positive x-axis
	5.54 N, 48.1° above the positive x-axis
	24.0 N, 18.8° above the negative x-axis
	11.9 N, 20.1° below the negative x-axis

Expert Solution

Step 1

Given:

Force $\vec{F_{1}} = 13.5 N$ makes an angle $19^{°}$ west of north.

Force $\vec{F_{2}} = 9.40 N$ towards east.

Force $\vec{F_{3}} = 7.20 N$ towards south.

Find:

The net force of given force vectors.

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