Neptune circles the Sun at a distance of 4.50 x 1012 m once every 164 years. Saturn circles the Sun at a distance of 1.43 x 1012 m. What is the orbital period of Saturn? a) 88.6 y 702 b) 109 h C) 29.4 y d) 304 y Boş bırak
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- 3. An unknown planet (mass is equal to 4.26 x 10^24 kg) is orbiting around the sun (mass of the sun is equal to 6.623703×1035kg). Knowing that the gravitational force between the unknown planet and the sun is (5.18 x 10^9)N, is the unknown planet nearer or farther to the sun compared to earth? (earth's distance to sun is 1 AU) Express your answer in terms of astronomical units or AU (1AU = 1.496 x 108 km). Assuming that the sun is fixated at a center point, calculate the area (in of the unknown planet's orbit (assume that the orbit is circle).a) Sketch the earth and mars, showing the center of the planets being separated by a distance d = 3 x 10^11 m. b). Use Newton's Universal Gravitation equation to determine the gravitational force of attraction between earth and mars at that distance given G= 6.7 x 10^-11 N x m^2/kg^2, mass of earth = 6 x 10^24 kg, mass of mars = 6.4 x 10^23 kgEarth Mars Saturn answers, include units 1 AU=1.496 x 10" m and Mun= 1.989 x 10 kg Mass of planet Radius of (kg) planet (km) 6371.0 3389.5 58,232 5.972x1024 6.417x102 5.683x102 Semimajor axis Eccentricity of Period of orbit of orbit a (AU) orbit e T (years) 1.00 0.0167 1.00 0.0934 1.88 0.0565 9.58 a) Use Kepler's 3rd Law to find the semimajor axis of Mars' orbit. AU m b) Use Kepler's 3rd Law to find the period of Saturn's orbit. c) Find the gravitational acceleration on the surface of Mars both in m/s² and as a multiple of Earth's gravitational acceleration. yrs m/s² g For (d) and (e), Earth's orbit is elliptical (ez0) but the semimajor axis is the average radius of the orbit so using the semimajor axis as the radius will let you solve for the average force and speed. d) Find the average force of gravity on the Earth from the Sun. e) Find the average speed of Earth as it moves around its orbit. N m/s
- What is the radius of geosynchronous orbit around the earth? (where the period of orbit is the same as the earths rotational period) Using the mass of the earth as me = 5.98 x 1024 kg and the sidereal day as 23 hours 56 minutes and 4.0905 s. Number Units2. The mean distance between the earth and the sun is 1.5 x 1011m. The mean distance between the sun and Venus is 1.08 x 108km. What is the period of Venus around the sun in earth- days?1) Give the following numbers to four significant figures in scientific notation: a) 0.0056542b) 93 842 773c) 0.000000100092d) 0.0095435 2) Repeat part (1), but this time give the numbers to two significant figures. 3) The radial acceleration, a, of a body rotating in a circle of radius r at constant speed v is given by ? =v2/rIf v = (3.00±0.05) m/s and r = (1.5±0.1) m, a) calculate a,b) the maximum values of a, c) minimum values of a, d) the uncertainty in a. 4) Linearize the following equations (rearranged in the form y = mx + c): a) ? = ?? , where F is the dependent variable, N is the independent variable and µ is the constant. b) ? = 2?√(?⁄?) where T is the dependent variable, l is the independent variable and g is the constant.i) What would you plot in order to obtain a straight line)? (Answer for a) and b)ii) How are the slope and intercept related to the constants in the equation? (Answer for a) and b)
- Assume the earth's mass is 80.004 x 1025 kg, and radius is 35.532 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.91 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s. Answer: Choose...Two planets orbit a star. You can ignore the gravitational interactions between the planets. Planet 1 has orbital radius r₁, and planet 2 has r₂ = 4r₁ Planet 1 orbits with period T₁ Planet 2 orbits with period A. T₂ = -1/T₁ B. T₂=2T₁ C. T₂ = 4T₁ D. T₂=8T₁
- The moon's period of revolution around the Earth is 27.3 d. How far away is the moon from the surface of the Earth? O A) 1.33× 107 m B) 3.83 × 108 m C) 3.77 × 108 m D) 4.88 × 10⁹ m2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?Consider the Earth's orbit around the Sun to be circular with radius R = 9.30 x 107 mi and it takes 365 days to complete one revolution. What is the distance Earth traveled for one revolution (circumference of a circle is 2??2πR )?