Neglecting air resistance, the path of a projectile that is propelled at an angle is y = g sec² 0 20² -x² ²+(tan0)x+h, 0≤0?

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This is part of a lesson plan for the calculus class I am taking. The solution is in the textbook, but I do not understand where they came up with the answers. I am looking for a different way to solve it so I can try to understand for my test. 

Neglecting air resistance, the path of a projectile that is propelled at an angle is
y=
g sec² 0
20²
-x²
²+(tan0)x+h, 0≤0</O
where y is the height, x is the horizontal distance, g is the acceleration due to gravity, vo is the
initial velocity, and h is the initial height. (This equation is derived in Section 12.3.) Let
g = 32 feet per second per second, vo = 24 feet per second, and h = 9 feet. What value of 0 will produce a
maximum horizontal distance?
Transcribed Image Text:Neglecting air resistance, the path of a projectile that is propelled at an angle is y= g sec² 0 20² -x² ²+(tan0)x+h, 0≤0</O where y is the height, x is the horizontal distance, g is the acceleration due to gravity, vo is the initial velocity, and h is the initial height. (This equation is derived in Section 12.3.) Let g = 32 feet per second per second, vo = 24 feet per second, and h = 9 feet. What value of 0 will produce a maximum horizontal distance?
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