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Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Problem 2 (Declaration Order, Sec. 3.3.3, 20 pts): Consider the following pseudocode. 1. procedure main a: integer : 1 b: integer : 2 2. 3. procedure middle b: integer :=a 4. 5. 6. procedure inner 7. print a, b 8. a: integer := 3 -- body of middle innero 9. 10. 11. print a, b 12. -- body of main middleo 13. 14. print a, b As can be seen from the pseudocode, this is a language that allows nested subroutines (middle is nested inside main and inner is nested inside middle). a) Suppose that this is a language with the declaration order rules of a language like C, i.e. names must be declared before use, and the scope of a name extends from its declaration through the end of the block. For each print statement (lines 7, 11, and 14), indicate which declarations of a and b are in the referencing environment (i.e. what declarations are they referring to). The declarations are lines that have the assignment to the variable (':='). • What numbers are output by the program? b) Suppose that this is a language with the declaration order rules of Modula-3, i.e. names can be declared in any order, and their scope is the entire block in which they are declared (see 3rd paragraph in pg. 132 of 4th edition or pg. 129 in 3rd edition of your textbook). • For each print statement (lines 7, 11, and 14), indicate which declarations of a and b are in the referencing environment. The declarations are lines that have the assignment to the variable (':='). • What numbers are output by the program?
Transcribed Image Text:Problem 2 (Declaration Order, Sec. 3.3.3, 20 pts): Consider the following pseudocode. 1. procedure main a: integer : 1 b: integer : 2 2. 3. procedure middle b: integer :=a 4. 5. 6. procedure inner 7. print a, b 8. a: integer := 3 -- body of middle innero 9. 10. 11. print a, b 12. -- body of main middleo 13. 14. print a, b As can be seen from the pseudocode, this is a language that allows nested subroutines (middle is nested inside main and inner is nested inside middle). a) Suppose that this is a language with the declaration order rules of a language like C, i.e. names must be declared before use, and the scope of a name extends from its declaration through the end of the block. For each print statement (lines 7, 11, and 14), indicate which declarations of a and b are in the referencing environment (i.e. what declarations are they referring to). The declarations are lines that have the assignment to the variable (':='). • What numbers are output by the program? b) Suppose that this is a language with the declaration order rules of Modula-3, i.e. names can be declared in any order, and their scope is the entire block in which they are declared (see 3rd paragraph in pg. 132 of 4th edition or pg. 129 in 3rd edition of your textbook). • For each print statement (lines 7, 11, and 14), indicate which declarations of a and b are in the referencing environment. The declarations are lines that have the assignment to the variable (':='). • What numbers are output by the program?
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