The necessary value for z2 was determined to be 1.645. Recall the given information.Sample 1Sample 2n1= 400n2= 300P1= 0.56P2= 0,39Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places.P1(1 - P1) P2(1 – P2)lower bound =P1P2 - Za/2V+n1n20.56(1 – 0.56)0.39(1 – 0.39)= 0.56 – 0.39- 1.645+400300=Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places.P1(1 - P1) , P2(1 – P2)upper boundP1 - P2 + Za/2\Vn1n20.56(1 – 0.56)0.39(1 – 0.39)+= 0.56 – 0.39+ 1.645400300Therefore, a 90% confidence interval for the difference in the population proportions (rounding to four decimal places) is from a lower bound ofto an upper bound of OEnter a number.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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n1=16 x‾1=124 s1=35 n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.
7.2.7-T Question Help Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t/2, (b) find the critical value z,12, or (c) 40- state that neither the normal distribution nor the t distribution applies. 30- The confidence level is 90%, o= 4084 thousand dollars, and the histogram of 55 player salaries (in thousands of dollars) of football players on a team is as shown. 20어 10- 0- 4000 8000 12000 16000 20000 Salary (thousands of dollars) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. t/2= (Round to two decimal places as needed.) O B. Za/2 = (Round to two decimal places as needed.) C. Neither the normal distribution nor the t distribution applies. kɔuənbə
Q-3) Show all the steps for the problem.
A sample of 1100 observations taken from a population produced a sample proportion of 0.38. Make a 90 % confidence interval for Round your answers to three decimal places. = ( ) to ( )
A simple random sample of size n=17 is drawn from a population that is normally distributed. The sample mean is found to be x= 69 and the sample standard deviation is found to be s= 20. Construct a 95% confidence interval about the population mean. ..... The lower bound is The upper bound is
Construct the indicated confidence interval for the population mean μ. (Round results to 3 decimal places.) 1. c = 0.80, x= 325, o 17, n = 89 = 2. c = 0.95, x = 188, o 12, n = 67 = 3. Tea consumption. A researcher wants to estimate the mean tea consumption of an organization. The tea consumption in pounds for 25 randomly selected tea drinkers in the organization were gathered. Their tea consumption is listed in Table 1. Assume that o = 1.0 pounds and the tea consumption follows a normal distribution. Construct a 95% confidence for the population mean. 1.9 3.4 1.9 2.3 1.2 Table 1. Tea consumption Tea Consumption (pounds) 4.5 2.8 2.8 3.2 0.9 2.3 3.4 1.7 2.6 1.9 3.6 2.9 3.3 2.4 2.9 3.2 2.9 2.8 3.1 2.0
6.2.9-T Construct the indicated confidence interval for the population mean u using the t-distribution. Assume the population is normally distributed. c = 0.95, x= 13.4, s= 3.0, n= 8 The 95% confidence interval using a t-distribution is (Round to one decimal place as needed.)
A random sample of n1n1 = 235 people who live in a city were selected and 79 identified as a "dog person." A random sample of n2n2 = 93 people who live in a rural area were selected and 67 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < p1−p2<

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