The table shows annual offshore crude oil production by a company in Mexico for the years 2008–2014, where \( t = 0 \) represents 2008.| Year \( t \) (year since 2008) | 0 | 1 | 2 | 3 | 4 | 5 | 6 ||-------------------------------|-----|-----|-----|-----|-----|-----|-----|| Offshore Crude Oil Production \( p \) (billion barrels) | 0.81 | 0.75 | 0.71 | 0.68 | 0.68 | 0.68 | 0.65 |(a) Use the table to compute the left and right Riemann sums for \( p(t) \) over the interval [1, 6] using five subdivisions.- Left Riemann sum: \_\_\_\_ billion barrels of offshore crude- Right Riemann sum: \_\_\_\_ billion barrels of offshore crude(b) What does the left Riemann sum in part (a) tell you about offshore crude oil production by the company?A total of \_\_\_\_ billion barrels of offshore crude were produced in the period \([2009 \text{ to } 2013]\).

In this question, concept of Riemann sum is applied. Riemann Sum To estimate ∫abfxdx, Riemann sums are utilised by approximating areas using the areas of rectangles or trapezoids. The width of each rectangle/trapezoid is x. Different ways of approximation are available depending on how we choose the height of the rectangles, including the trapezoidal method.The Left Hand Rule, the Right Hand Rule, and the Midpoint Rule are three standard methods for the height of these rectangles. The Left Hand Rule states that the function should be evaluated at the sub-interval's left-hand endpoint and the rectangle should be that height. The Right Hand Rule says to evaluate the function at the right endpoint on each sub-interval and make the rectangle that height. a) Given interval is 1,6 and five subdivisions.(n=5) ∆x=6-15=1 Intervals are 1,2,2,3,3,4,4,5 and 5,6 For Left Riemaan Sum ∆xp1+p2+p3+p4+p5=10.75+0.71+0.68+0.68+0.68 =3.5 For Right Riemann Sum ∆xp2+p3+p4+p5+p6=10.71+0.68+0.68+0.68+0.65 =3.4b) Left riemann sum in part (a) tell 3.5 billion barrels of offshore crude were produced.