The following functions/statements are useful to solve the probler:• The pow function from the library: e.g. pow(x.y) gives the value of x• The rand( ) function from the library: rand( ) gives a random integer between 0 andRAND_MAX, where RAND_MAX is a predefined constant integer in C++.When you use rand( ) make sure to include the empty braces (you will understand what they meanlater when you learn about C++ functions).The srand(time(0)); statement at the beginning of main which requires adding the library.This statement is needed if you want the program to give different random values for different runs.The use of srand(time(0)) is optional; i.e. no grades will be deducted if you do not include it. Write a C++ program that performs the following (see the Appendix for useful functions):(a) Prompt the user to enter two positive integers n and m (you are not required to handle the case whenn or m are not positive), and a real number z (z is real, i.e it can be a decimal and it can be negative).Read the values entered by the user and store them in variables of appropriate data types.(b) Ask the user to enter one of two choices:- 'd' or 'D' for deterministic sum- T' or 'R' for random producto If the user's choice is a deterministic sum, then compute and print the following summation (wheren, m, and z are the values entered in part a):m+nkdet sum = 2((-1)*)z x kk=no Otherwise, if the choice is a random product, then compute and print the following random product(where n, m, and z are the values entered in part a, and rg is a random decimal number between 0and 1 inclusive):m+n[]a +r)rand prod = z x(1+k=nNote: Notice that rg depends on k, this means that you need to generate a new randomdecimal in the range [0,1] for each k.o If the user enters an invalid choice (any character other than 'd', 'D', 'r', or 'R'), print an errormessage.(c) Update the program to allow the user to repeat (enter new values of n, m, and z, and a new choice),and display the new results for the new inputs. Your program will never stop (it will keep asking theuser for new input after each run)

In this question, we need to make the program as such, that it never stops and keeps ongoing. For…

Answered: nd( ) function from the library: rand(…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Write a program in C++ code:
your goal is to modify your assignment 6 program to allow the user to pick up a random item and display a sorted list of the contents of the knap sack. note: if you use the built in c++, the most you can make on this assignment is 4 out of 10. you are expected to right your own sort based on one of the algorithms covered in class. your program should have the following: • the name of the program should be assignment 6. • 3 comment lines (description of the program, author, and date). • modify your assignment 5 program to do the following: o display a menu (use a switch statement to implement the menu) of actions ▪ attack: • for now, just display that the user chose to attack ▪ pick up item: • randomly add one of 6 items to an array named knapsack o you get to choose the item names • display which item the user picked up ▪ add an option to the main switch statement: display knap sack contents • the contents of the knap sack must be sorted The knapsack items are bananas, lays,…
I wrote this c++ program to find min and max, but why does the program say it cannot find the min and max. WHere I got wrong? Please help me revise my code. I have must use the pointer and void function in my code. Please help me revise it. #include <iostream>using namespace std; int getmin(int number[], int size){ int min=number[0]; for (int i=1; i<size; i++) { if (number[i]<min) min=number[i]; } return min;}int getmax(int number[], int size){ int max=number[0]; for (int i=1; i<size; i++) { if (number[i]>max) max=number[i]; } return max;}void getminandmax(int number[], int size, int* min, int* max) { for (int i=1; i<size; i++) { if (number[i] > *max) *max=number[i]; if (number[i] < *min) *min=number[i]; } } int main(){ int number[5]={5, 4, -2, 29, 6}; int min=number[0]; int max=number[0]; getminandmax(number, 5, &min, &max);…
please code this for me in c++ using void, functions, loops, (basic c++ not complicated or highlevel please). I tried to code it myself but there are many mistakes I dont know how to fix so please write a similar one for me but it works. The question is only 1 but it has 2 parts (2 different functions that should be in one code) MY CODE: #include <iostream>using namespace std; int IsPalindrome(int p);void GCD(); int main (){ int choice; cout << "Please enter a choice: "<<endl; cout << "Enter one for IsPalindrome "<<endl; cout << "Enter 2 for GCD "<<endl; cout << "Enter 3 to exit the program "<<endl; cout << "Choice: "<<endl; cin >> choice; if (choice == 1) { int p; cout << "Please enter a 3 digit number: "<<endl; cin >> p; if(p%10==p/100) { cout<<p<<" is a palindrome " <<endl; } else {…
in the C++ version please suppose to have a score corresponding with probabilities at the end and do not use the count[] function. Please explain the detail when coding. DO NOT USE ARRAY. The game of Pig The game of Pig is a dice game with simple rules: Two players race to reach 100 points. Each turn, a player repeatedly rolls a die until either a 1 ("pig") is rolled or the player holds and scores the sum of the rolls (i.e. the turn total). At any time during a player's turn, the player is faced with two decisions: roll - if the player rolls 1: the player scores nothing and it becomes the opponents turn. 2 - 6: the number is added to the player's turn total and the player's turn continues. hold - The turn total is added to the player's score and it becomes the opponent's turn. This game is a game of probability. Players can use their knowledge of probabilities to make an educated game decision. Assignment specifications Hold-at-20 means that the player will choose to roll…
In C++ fill in the blanks
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