Natural selection acts on MEIOS Paternal Maternal chromosome red) chromosome Homologous chromosomes we paired all along their lengthe genetic variation. The ultimate source of genetic variation is mutation in the DNA (or RNA in some organisms). However, in sexually reproducing organisms with a long generation time, what process(es) account(s) for individual variation? (blue) Centromere Metaphase- plate Chiasma Nonsister chromatids form chiasma Homologous segments cross over, producing hybrid chromosomes Homologous pairs separate into recombinant chromosomes. When the homologous chromosomes separate in maphase L half contain a new egment originating trom the other member of the homologous pair. MEIOSIS I a) random fertilization Sister chromatids separate each going to a different gamete. Recombinant chromosomes Result: two parental chromosomes that match the originals, and tw recombinant chromosomes with new gene combinations. b) crossing over Parental chromosomes c) independent assortment d) all of the above

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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re paired at
3. Concept Check
Natural selection acts on
Maternal
chromosome
(red)
MEIOSISI
Paternal
chromosome
(blue)
Homologous e
genetic variation. The ultimate
source of genetic variation is
mutation in the DNA (or RNA in
some organisms). However, in
sexually reproducing organisms
with a long generation time,
what process(es) account(s)
Centromere
Metaphase-
plate
lengths
Chiasma
Nonsister chromatids form
chiasma. Homologous segments
cross over, producing hybrid
chromosomes
Homologous pairs separate into
recombinant chromosomes,
When the homologous
chromosomes separate in
for individual variation?
anaphase L half contain a new
segment originating from the
other member of the
homologous pair.
MEIOSIS I
a) random fertilization
Sister chromatids separate
each going to a different
gamete.
b) crossing over
Recombinant
chromosomes
Result:
ut two parental
chromosomes that match the
originals, and two
Parental chromosomes
recombinant chromosomes
c) independent assortment
with new gene combinations.
d) all of the above
© 2018 Pearson Education, Inc
4. Concept Check
Evolutionary fitness is an often misunderstood concept. Which of
the following imaginary individuals would have the greatest
evolutionary fitness?
a) sparrow A
b) sparrow B
c) sparrow C
d) sparrow D
Sparrow A
Sparrow B
Sparrow C
Sparrow D
Beak size (mm)
13
15
17
16
Life span (years)
2.5
3
3
Offspring that
survive to
10
16
12
14
adulthood
© 2018 Pearson Education, Inc.
5. Interpreting Data
The figure below shows the frequency of foot phenotypes in a
population of blue-footed boobies. What is the frequency of the W
allele in this population?
a) 0.2
b) 0.4
Phenotypes
c) 0.8
Genotypes
ww
Ww
ww
d) 0.6
Number of animals
320
160
20
(total = 500)
Transcribed Image Text:re paired at 3. Concept Check Natural selection acts on Maternal chromosome (red) MEIOSISI Paternal chromosome (blue) Homologous e genetic variation. The ultimate source of genetic variation is mutation in the DNA (or RNA in some organisms). However, in sexually reproducing organisms with a long generation time, what process(es) account(s) Centromere Metaphase- plate lengths Chiasma Nonsister chromatids form chiasma. Homologous segments cross over, producing hybrid chromosomes Homologous pairs separate into recombinant chromosomes, When the homologous chromosomes separate in for individual variation? anaphase L half contain a new segment originating from the other member of the homologous pair. MEIOSIS I a) random fertilization Sister chromatids separate each going to a different gamete. b) crossing over Recombinant chromosomes Result: ut two parental chromosomes that match the originals, and two Parental chromosomes recombinant chromosomes c) independent assortment with new gene combinations. d) all of the above © 2018 Pearson Education, Inc 4. Concept Check Evolutionary fitness is an often misunderstood concept. Which of the following imaginary individuals would have the greatest evolutionary fitness? a) sparrow A b) sparrow B c) sparrow C d) sparrow D Sparrow A Sparrow B Sparrow C Sparrow D Beak size (mm) 13 15 17 16 Life span (years) 2.5 3 3 Offspring that survive to 10 16 12 14 adulthood © 2018 Pearson Education, Inc. 5. Interpreting Data The figure below shows the frequency of foot phenotypes in a population of blue-footed boobies. What is the frequency of the W allele in this population? a) 0.2 b) 0.4 Phenotypes c) 0.8 Genotypes ww Ww ww d) 0.6 Number of animals 320 160 20 (total = 500)
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