I have a question about this problem working on it study group my friend says the ee is already a percent and you would add the 12.5% because the remaining 25% is the race mix and s is half of the race mix. I am lost because I thought to find the ee you do ( observed rotation/ the specific rotation) which is what the majority of online sites say I got 0.748 &74.8 or 75% and they got 75 & 87 can someone please help and explain, I have also attached an image of what my professor said as well. Natural camphor ((+)-1R, 4R) has a specific rotation of +44.1°.3)a) If a particular sample of camphor has a rotation [a]p of +33°, what is theenantiomeric excess?The ee is:Camphorb) What fraction of the sample (in percent) is the (1R, 4R) enantiomer?Percent (1R, 4R) is: The definition of ee (well, it's one way to define it) isalpha observed divided by alpha of a pure sample(concentrations and path lengths divided out inboth).The second part requires that you calculate totalamount of each enantiomer. If the sample is 50%ee, then 50% of the sample is a major enantiomerand the remaining 50% is racemic. Racemic is a 1:1mixture of enantiomers, so half of the 50% racemic(25%) is the major enantiomer. With that, youcalculate the total fraction of the sample that is themajor enantiomer, which in the example above is75%.

(a) The formula to calculate the enantiomeric excess or optical purity is given by: ee = observed…

Answered: Natural camphor ((+)-1R, 4R) has a…

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

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I have a question about this problem working on it study group my friend says the ee is already a percent and you would add the 12.5% because the remaining 25% is the race mix and s is half of the race mix. I am lost because I thought to find the ee you do ( observed rotation/ the specific rotation) which is what the majority of online sites say I got 0.748 &74.8 or 75% and they got 75 & 87 can someone please help and explain, I have also attached an image of what my professor said as well.

Natural camphor ((+)-1R, 4R) has a specific rotation of +44.1°.
3)
a) If a particular sample of camphor has a rotation [a]p of +33°, what is the
enantiomeric excess?
The ee is:
Camphor
b) What fraction of the sample (in percent) is the (1R, 4R) enantiomer?
Percent (1R, 4R) is:

The definition of ee (well, it's one way to define it) is
alpha observed divided by alpha of a pure sample
(concentrations and path lengths divided out in
both).
The second part requires that you calculate total
amount of each enantiomer. If the sample is 50%
ee, then 50% of the sample is a major enantiomer
and the remaining 50% is racemic. Racemic is a 1:1
mixture of enantiomers, so half of the 50% racemic
(25%) is the major enantiomer. With that, you
calculate the total fraction of the sample that is the
major enantiomer, which in the example above is
75%.

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