NASA launches a rocket at t =0 seconds. Its height, in meters above sea-level, as a function of time is given by = - 4.9t + 325t + 346. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? (Round to the nearest tenth.) The rocket splashes down after seconds. How high above sea-level does the rocket get at its peak? (Round to the nearest tenth.) The rocket peaks at meters above sea-level.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by
h(t) = – 4.9t + 325t + 346.
Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? (Round to the
nearest tenth.)
The rocket splashes down after
seconds.
How high above sea-level does the rocket get at its peak? (Round to the nearest tenth.)
The rocket peaks at
meters above sea-level.
Transcribed Image Text:NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = – 4.9t + 325t + 346. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? (Round to the nearest tenth.) The rocket splashes down after seconds. How high above sea-level does the rocket get at its peak? (Round to the nearest tenth.) The rocket peaks at meters above sea-level.
Expert Solution
Step 1

Given that, the function is ht=-4.9t2+325t+346.

it is known that, the height of the rocket will be zero when the rocket splash down into ocean.

Substitute h(t)=0 in  ht=-4.9t2+325t+346.

0=-4.9t2+325t+346t=-1.04805 or t=67.37458t-1.03 or t67.37

Note that, the time never be negative, ignore the negative root t=-1.03.

Therefore, the splash down will occur after 67.37 seconds.

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