A buoyant object is dropped into a tank full of liquid. The height of the object above the bottom of the tank t seconds after entering the liquid is given by: h(t) = 2.4t2 – 6t +7 feet. How far above the bottom of the tank is the object at its lowest point and when does this occur?

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A buoyant object is dropped into a tank full of liquid. The height of
the object above the bottom of the tank t seconds after entering
the liquid is given by: h(t) = 2.4t² - 6t +7 feet.
How far above the bottom of the tank is the object at its lowest
point and when does this occur?
Write your answers on the respective blanks provided. Type each
answer as a number. If rounding is necessary, use 3 decimal places.
Do not include units!
The lowest height is
feet.
Time lowest height occurs
seconds.
Transcribed Image Text:A buoyant object is dropped into a tank full of liquid. The height of the object above the bottom of the tank t seconds after entering the liquid is given by: h(t) = 2.4t² - 6t +7 feet. How far above the bottom of the tank is the object at its lowest point and when does this occur? Write your answers on the respective blanks provided. Type each answer as a number. If rounding is necessary, use 3 decimal places. Do not include units! The lowest height is feet. Time lowest height occurs seconds.
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