Name the random variables present in the table above. Carefully define the null and alternative hypotheses of the Chi Square test underlying the generation of the above table.
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Test is that whether the ages of its employees are related to the department that they work in.
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- A grocery store says their mangoes are fresher than most. A typical grocery store has roughly 10% go bad before they sell. A random sample of 135 mangoes from the store showed that 13 of the mangoes were rotten. Assume we have a significance level of 0.05. 1. null hypothesis____________ the alternative hypothesis is__________ 2. Our z-test statistic is 3. Our p-value is 4. evidence supporting the alternative?We want to assess three new medicines (FluGone, SneezAb, and Fevir) for the flu, Whích of the following could NOT be a block in this study? FluGone Age of patients Gender of patients Severity of adverse reaction A scientist who has collected univariate data should use a scatterplot to graph the data. True False Which of the follow are NOT conditions for a two-sample t-test? O Samples must be obtained using simple random sampling Samples are dependent Variable of measure is categorical Variable distribution is approximately normal 2 points 0000 O000A new vaccination is being used in a laboratory experiment to investigate whether it is effective. There are 282 subjects in the study. Is there sufficient evidence to determine if vaccination and disease status are related? Vaccination Status Diseased Not Diseased Total Vaccinated 54 124 178 Not Vaccinated 71 33 104 Total 125 157 282 Copy Data Step 7 of 8: Make the decision to reject or fail to reject the null hypothesis at the 0.025 level of significance.
- Use the attached standard normal table to find the p-value for the given hypothesis test. Ho: p = .3, H1: p7.3 (two tailed test), the test statistic is Z = -2.16. What is the p-value? Do not round your answer.☐True ☐False As a general rule, as the sample size increases the probability of rejecting the null hypothesis decreases.Find the expected counts in each category using the given sample size and null hypothesis. Ho: P₁ P₂ = P3 = P4 = 0.25; n Enter the exact answers. Category Expected count 1 2 = 700 3 i 4
- A "Gallup poll" is a national public opinion poll run by Gallup, Inc. According to the company's website, a typical sample size for a phone-based Gallup poll is 1000 randomly-selected adults, and poll results are said to be representative of the opinions of all Americans within a margin of error of ±4 percentage points. What methods do you think Gallup, Inc. must use to ensure true random selection of all 1000 phone participants? Give at least 3 methods. Hint: Consider how lists of phone numbers are generated, which types of phone lines are called, the timing of calls, and how participants are selected when one phone number could be associated with various members of a household.A QR code photographed in poor lighting, so that it can be difficult to distinguish black and white pixels. The gray color (X) in each pixel is therefore coded on a scale from 0 (white) to 100 (black). The true pixel value (without shadow) the code is Y = 0 for white, and Y = 1 for black. We treat X and Y as random variables. For the highlighted pixel in the figure is the gray color X = 20 and the true pixel value is white, i.e. Y = 0. We assume that QR codes are designed so that, on average, there are as many white as black pixels, which means that pY (0) = pY (1) = 1/2. In this situation, X is continuously distributed (0 ≤ X ≤ 100) and Y is discretely distributed, but we can still think about the simultaneous distribution of X and Y. We start by defining the conditional density of X, given the value of Y : fX|Y(x|0) = "Pixel is really white" fX|Y(x|1) =" Pixel is really balck " Use Bayes formula as given in the picture and find the probability for x = 20 like in the picture.A travel company is investigating whether the average cost of a hotel stay in a certain city has increased over the past year. The company recorded the cost of a one-night stay for a Friday night in January of the current year and in the previous year for 31 hotels selected at random. The difference in cost (current year minus previous year) was calculated for each hotel. Which of the following is the appropriate test for the company’s investigation? A one-sample zz-test for a population mean A A one-sample tt-test for a sample mean B A one-sample zz-test for a population proportion C A matched-pairs tt-test for a mean difference D A two-sample tt-test for a difference between means E
- K Two different simple random samples are drawn from two different populations. The first sample consists of 20 people with 11 having a common attribute. The second sample consists of 1900 people with 1353 of them having the same common attribute. Compare the results from a hypothesis test of p₁ = P₂ (with a 0.01 significance level) and a 99% confidence interval estimate of P₁-P₂- What is the conclusion based on the hypothesis test? The test statistic is the critical region, so The 99% confidence interval is < (P₁-P₂) < (Round to three decimal places as needed.) What is the conclusion based on the confidence interval? Since 0 is the null hypothesis. How do the results from the hypothesis test and the confidence interval compare? The results are since the hypothesis test suggests that p₁ the null hypothesis. There is in the interval, it indicates to evidence to conclude that p₁ # P₂. P₂, and the confidence interval suggests that p₁ VP2- DSuppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 24%. Use a 0.10 significance level to test that claim. H: p>U.24 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho- There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O B. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% OC. Fail to reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O D. Reject Ho. There is sufficient…Please answer the following question and show work! Answer all parts. Thank you