Name Mass Formula Mass moles Draw v Calculations T Read aloud Ba(OH)₂ + 2Na₂SO4 → BaSO+2NaOH 1200g 171.34 g/mol 2500g 142.04 g/mol A 233.39 g/mol 40.00 g/mol

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question
100%
Fill in with steps
### Chemical Reaction: Barium Hydroxide and Sodium Sulfate

In this experiment, we observe the chemical reaction between barium hydroxide and sodium sulfate:

\[ \text{Ba(OH)}_2 + 2\text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaOH} \]

#### Reactants and Products Information

1. **Ba(OH)₂**:
   - **Mass**: 1200 g
   - **Formula Mass**: 171.34 g/mol

2. **2Na₂SO₄**:
   - **Mass**: 2500 g
   - **Formula Mass**: 142.04 g/mol

3. **BaSO₄**:
   - **Formula Mass**: 233.39 g/mol

4. **2NaOH**:
   - **Formula Mass**: 40.00 g/mol

#### Moles Calculation
- Use the formula:

  \[
  \text{Moles} = \frac{\text{Mass}}{\text{Formula Mass}}
  \]

Complete calculations based on the formula mass and given mass of each substance.

#### Explanation
This setup helps in understanding stoichiometry by calculating the moles of each reactant and product. The reaction showcases the formation of barium sulfate (a precipitate) and sodium hydroxide from the reaction of barium hydroxide with sodium sulfate.
Transcribed Image Text:### Chemical Reaction: Barium Hydroxide and Sodium Sulfate In this experiment, we observe the chemical reaction between barium hydroxide and sodium sulfate: \[ \text{Ba(OH)}_2 + 2\text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaOH} \] #### Reactants and Products Information 1. **Ba(OH)₂**: - **Mass**: 1200 g - **Formula Mass**: 171.34 g/mol 2. **2Na₂SO₄**: - **Mass**: 2500 g - **Formula Mass**: 142.04 g/mol 3. **BaSO₄**: - **Formula Mass**: 233.39 g/mol 4. **2NaOH**: - **Formula Mass**: 40.00 g/mol #### Moles Calculation - Use the formula: \[ \text{Moles} = \frac{\text{Mass}}{\text{Formula Mass}} \] Complete calculations based on the formula mass and given mass of each substance. #### Explanation This setup helps in understanding stoichiometry by calculating the moles of each reactant and product. The reaction showcases the formation of barium sulfate (a precipitate) and sodium hydroxide from the reaction of barium hydroxide with sodium sulfate.
Expert Solution
steps

Step by step

Solved in 7 steps with 16 images

Blurred answer
Knowledge Booster
Ionic Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY