Name: Date: Chi Square - Simple Problems X² = %3D x* critical values probability df 90 50 .10 .05 .025 995 .000 .016 .010 .211 2.706 3.841 5.024 .455 1.386 4.605 5.991 7.378 2.366 6.251 7.815 9.348 1 072 584
Name: Date: Chi Square - Simple Problems X² = %3D x* critical values probability df 90 50 .10 .05 .025 995 .000 .016 .010 .211 2.706 3.841 5.024 .455 1.386 4.605 5.991 7.378 2.366 6.251 7.815 9.348 1 072 584
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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I need help with both the charts please
![Date:
Name:
(0-e)
Chi Square - Simple Problems
X² =
Σ
x* critical values
probability
.10
2.706 3.841
df
.90
.50
.05
.025
.995
.000 .016
.211
1
.455
5.024
.010
1.386 4.605 5.991
7.378
3
.072
.584
2.366 6.251 7.815 9.348
4.
.207 1.064 3.357 7.779 9.488
11.143
1. If two brown mice are bred together, 35 of their 100 offspring are white.
You hypothesize that the parents are heterozygous (Bb x Bb), support your claim
using a chi square.
ta (or
h esuh
Observed
Expected
(Observed - Expected)?
Expected
Brown Mice
White Mice
Summed X =
ANALYSIS: .
2. A litter of mice was found in the lab, but no one wrote down what their parents were. In this type of mouse, ears
can be curled due to a recessive allele. In the unknown litter, 8 mice have curled ears and 6 mice have normal ears.
You hypothesize that the parents were Bb x bb. Support your claim with a chi square analysis.
Observed
Expected
(Observed - Expected)?
Expected
Curled Ears
Normal Ears
Summed X =
ANALYSIS:
www.hiologvcorner.com](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6d03926-2370-4876-aaac-56edea5a7e63%2F22e69e0a-c45f-4750-a948-499cbb52a069%2Fe0wk8f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Date:
Name:
(0-e)
Chi Square - Simple Problems
X² =
Σ
x* critical values
probability
.10
2.706 3.841
df
.90
.50
.05
.025
.995
.000 .016
.211
1
.455
5.024
.010
1.386 4.605 5.991
7.378
3
.072
.584
2.366 6.251 7.815 9.348
4.
.207 1.064 3.357 7.779 9.488
11.143
1. If two brown mice are bred together, 35 of their 100 offspring are white.
You hypothesize that the parents are heterozygous (Bb x Bb), support your claim
using a chi square.
ta (or
h esuh
Observed
Expected
(Observed - Expected)?
Expected
Brown Mice
White Mice
Summed X =
ANALYSIS: .
2. A litter of mice was found in the lab, but no one wrote down what their parents were. In this type of mouse, ears
can be curled due to a recessive allele. In the unknown litter, 8 mice have curled ears and 6 mice have normal ears.
You hypothesize that the parents were Bb x bb. Support your claim with a chi square analysis.
Observed
Expected
(Observed - Expected)?
Expected
Curled Ears
Normal Ears
Summed X =
ANALYSIS:
www.hiologvcorner.com
Expert Solution
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Step 1
Chi square test is goodness of fit test.
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