Name: -11. The graph of the function y=x2-6x+ 8 is: 12 X Find the coordinates of its vertex and its intercepts. vertex (-3, 1); x-intercepts-2, 4; y-intercept 7 b. a. vertex (3,-1); x-intercepts 8; y-intercept 2, 4 vertex (4, 2); x-intercepts 8, 7; y-intercept 2 d. are c. vertex (3, -1); x-intercepts 2, 4; y-intercept 8 vertex (6,-2); x-intercepts 3, 6; y-intercept 6 For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh. e. 12. %3D %3D (fog•h)(x) = (~F - 10) +3 (fogoh)(x) = x' +x-7+ /x gogoh)(x) = (~x -7)' a. b. %3D C. d. (fogoh)(x) = /x -7 e. fogoh)(x) = (x' +3)+ (x – 10)~/x %3D %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Name:
-11. The graph of the function y=x2-6x+ 8 is:
12 X
Find the coordinates of its vertex and its intercepts.
vertex (-3, 1); x-intercepts-2, 4; y-intercept 7
b.
a.
vertex (3,-1); x-intercepts 8; y-intercept 2, 4
vertex (4, 2); x-intercepts 8, 7; y-intercept 2
d.
are
c.
vertex (3, -1); x-intercepts 2, 4; y-intercept 8
vertex (6,-2); x-intercepts 3, 6; y-intercept 6
For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh.
e.
12.
%3D
%3D
(fog•h)(x) = (~F - 10) +3
(fogoh)(x) = x' +x-7+ /x
gogoh)(x) = (~x -7)'
a.
b.
%3D
C.
d. (fogoh)(x) = /x -7
e. fogoh)(x) = (x' +3)+ (x – 10)~/x
%3D
%3D
Transcribed Image Text:Name: -11. The graph of the function y=x2-6x+ 8 is: 12 X Find the coordinates of its vertex and its intercepts. vertex (-3, 1); x-intercepts-2, 4; y-intercept 7 b. a. vertex (3,-1); x-intercepts 8; y-intercept 2, 4 vertex (4, 2); x-intercepts 8, 7; y-intercept 2 d. are c. vertex (3, -1); x-intercepts 2, 4; y-intercept 8 vertex (6,-2); x-intercepts 3, 6; y-intercept 6 For f(x) = x' +3, g(x) = x- 10, and h(x) = x find fogoh. e. 12. %3D %3D (fog•h)(x) = (~F - 10) +3 (fogoh)(x) = x' +x-7+ /x gogoh)(x) = (~x -7)' a. b. %3D C. d. (fogoh)(x) = /x -7 e. fogoh)(x) = (x' +3)+ (x – 10)~/x %3D %3D
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