Na3AlF6 is synthesized according to the following reaction. Al2O3 (k) + 6 NaOH (aq) + 12HF (g) à 2 Na3AlF6 (k) + 9 H2O (s)   In an experiment; 6.55 g Al2O3 and excess HF were dissolved in 1.75 L of 0.15 M NaOH . If 20 g Na3AlF6 were obtained at the end of the experiment, What is the limiting reagent? What is the real yield? What is the theoretical yield? What is % yield (percentage yield

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