Na2S2O3 (aq) + 4 Cl2 (g) + 5 H2O (aq) ---> 2 NaHSO4 (aq) + 8 HCl (aq) 168 grams of HCl were generated from the reaction shown by the equation, below. How much chlorine gas (Cl2) was destroyed during this process?

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Chapter1: Introduction To Chemistry
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Na2S2O3 (aq) + 4 Cl2 (g) + 5 H2O (aq) ---> 2 NaHSO4 (aq) + 8 HCl (aq)

168 grams of HCl were generated from the reaction shown by the equation, below. How much chlorine gas (Cl2) was destroyed during this process?

 

Molar masses of solid chemical (given or desired) must be calculated if it is not provided in the context of the problem.

First, calculate molar mass. An example of how to is attached.

 

Next, set up and solve the problem exactly like the example attached.

5XG=6x12.011 = 72.065
12x M 12x1000 - 12.096
5x0=6x15.999 = 95.994
- 180.156 g/mol
6 sig figs
r
Transcribed Image Text:5XG=6x12.011 = 72.065 12x M 12x1000 - 12.096 5x0=6x15.999 = 95.994 - 180.156 g/mol 6 sig figs r
How many grams of barium nitrate (Ba(NO₂), are produced from 5.0 g
of silver nitrate (AgNO,) reacting with an excess of barium chloride??
2AgNO3(a) + BaCl₂ (s) -Ba(NO3)2 (s) + 2AgCl (s)
moles
5.0 g
more than
enough
Molar masses of all compounds in the equation:
AgNO3: 169.88 g/mol
Ba(NO3)2:
BaCl₂: 208.23 g/mol
AgCl:
Setup & solve the problem, below:
5.0 g AgNO3 1 mol AgNO3
1 mol Ba(NO3)2
169.88 g AgNO3 2 mol AgNO3
3.8 g Ba(NO3)2
261.35 g/mol
143.32 g/mol
261.35 g Ba(NO3)2
1 mol Bo(NO3)2
1306.75/339.76
3.84609724
3.8 g Ba (NO3)2
Transcribed Image Text:How many grams of barium nitrate (Ba(NO₂), are produced from 5.0 g of silver nitrate (AgNO,) reacting with an excess of barium chloride?? 2AgNO3(a) + BaCl₂ (s) -Ba(NO3)2 (s) + 2AgCl (s) moles 5.0 g more than enough Molar masses of all compounds in the equation: AgNO3: 169.88 g/mol Ba(NO3)2: BaCl₂: 208.23 g/mol AgCl: Setup & solve the problem, below: 5.0 g AgNO3 1 mol AgNO3 1 mol Ba(NO3)2 169.88 g AgNO3 2 mol AgNO3 3.8 g Ba(NO3)2 261.35 g/mol 143.32 g/mol 261.35 g Ba(NO3)2 1 mol Bo(NO3)2 1306.75/339.76 3.84609724 3.8 g Ba (NO3)2
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