AN88 28' 24"E258.182 MA traverse from A to H is shown from theS87* 33' 16"E5figure below. Inside the traverse is a162.867M1lot.a. Adjust the traverse by compassrule. Tabulate your computation.b. Calculatethecoordinates ofstation F if station A has N =3.s88° 53' 56"W144.666M20000.000, E = 20000.000c. If station F to corner 4 has bearing117.396 M161.965 Mand distance equal to N 33° 56' 46"W and 86.985 m, calculate thecoordinates of all lot corners.143.069 MHN86 33' 16"WGN6* 15 27E204.152MN3° 12' 25"E552.815 M115.385MS21* 56' 27"E134.863 MS37' 45' 45"E119.958M$44' 04' 37"w240.608 MS6° 34' 12"E146.178 Mso° 40' 28"E

(a) Adjust the traverse by compass rule Latitude = L cos θ Departure = L Sin θ Lines Distance…

N88 28' 24"E A B 258.182 M A traverse from A to H is shown from the S87' 33' 16"E figure below. Inside the traverse is a 162.867M 1 lot. a. Adjust the traverse by compass rule. Tabulate your computation. b. Calculate the coordinates of station F if station A has N = %3D 4 144.666M 20000.000, E = 20000.000 %3D s88° 53' 56"W c. If station F to corner 4 has bearing 117,396 M 161.965 M and distance equal to N 33° 56' 46" W and 86.985 m, calculate the coordinates of all lot corners. 143.069 M H N86 33' 16*W G N3 12' 25"E 552.815 M N6* 15' 27"E 204.152M 115.385M S21 56' 27"E 134.863 M S37' 45' 45"E G 119.958M S44' 04' 37"W 240.608 M S6* 34' 12"E 146.178 M So° 40' 28"E

N88 28' 24"E A B 258.182 M A traverse from A to H is shown from the S87' 33' 16"E figure below. Inside the traverse is a 162.867M 1 lot. a. Adjust the traverse by compass rule. Tabulate your computation. b. Calculate the coordinates of station F if station A has N = %3D 4 144.666M 20000.000, E = 20000.000 %3D s88° 53' 56"W c. If station F to corner 4 has bearing 117,396 M 161.965 M and distance equal to N 33° 56' 46" W and 86.985 m, calculate the coordinates of all lot corners. 143.069 M H N86 33' 16W G N3 12' 25"E 552.815 M N6 15' 27"E 204.152M 115.385M S21 56' 27"E 134.863 M S37' 45' 45"E G 119.958M S44' 04' 37"W 240.608 M S6* 34' 12"E 146.178 M So° 40' 28"E

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Compute the distance only between points "A" and point "B" Point A- N 1147.8000 E 710.4700 Point B N…

A: Given values: Point A: N 1147.8000 E 710.4700 Point B: N 1489.1700 E 138.5700

Q: and accurately the interior angles of the traverse.

A: This question is from Surveying.

Q: A closed traversed has the following data. LINE DISTANCE BEARING AB 185.33 N 43 E BC 258.28 S 67 E…

A: To find length of CD

Q: 25. Find the radius of the circle passing through the points A, B, C, whose coordinates are shown…

A: Find: Radius of circle passing through the points A, B and C

Q: Given the following data for a closed traverse for which the bearing of AB and the distance of DE…

Q: A. Compute the azimuths (from the north) given the bearing of course AB and the angles to the right…

Q: 25) Calculate coordinates of station (65+10.00) on the horizontal circular curve (R= 750 m, 4=…

Q: A closed traverse was surveyed and the resulting values of latitudes and departures were computed.…

Q: From the following traverse notes, compute the corrected distance of line CD using Transit Rule.…

Q: Question 1:- In the traverse ABCDEA, the following angles and lengths are measured: Length (m) Angle…

A: Theoretical sum of Angles of a closed traverse = 540° Computed sum of interior angles = 538°30'48''…

Q: Problem 1. The following data relate to a closed traverse ABCD in which the bearings of the lines AB…

Q: A closed traverse has the following data: Distance Line Bearing Latitude Departure (m) 1081 S…

A: LINE DISTANCE BEARING LATITUDE=Lcosθ DEPARTURE=Lsinθ AB 1081 S73°47'E -301.89 +1037.03 BC…

Q: 3. From Figure 3.1 calculates angular error, traverse accuracy, adjusted coordinate (N, E), adjusted…

A: Data givenFind:(a) Angular error(b) Traverse accuracy(c) Adjusted coordinate(d) Adjusted distance(e)…

Q: Determine the area (hectares) within the traverse using DMDS. Course Dep Lat AB -221.351 27.185 ВС…

Q: Given the closed traverse data. Lines Bearing Distance AB N20o E 20.35…

Q: X8-1. The adjusted clockwise interior angles of a traverse which originates and closes at point A…

A: Given:

Q: Q9) The bearing of the sides of a closed traverse ABCDEA are as follow: Side F.B B.B AB 107° 15'…

Q: From field notes of a closed traverse shown below, adjust the traverse using Transit Rul e area…

Q: Part B Calculate the y-coordinates for the other stations. Express your answers, separated by…

Q: Problem. The coordinates of the loop traverse are given below. a. Compute for the bearing and length…

A: Calculate length using formula L=(∑Latitude)2+∑(Departure)2 Calculate bearing using formula…

Q: Convert 2489 Psi to GPa .000043 .017155 .171551 .000434

A: Convert 2489 Psi to ______ GPa We know that 1 psi = 6.8947572931783E-6 GPa Then 2489 psi = 2489 x…

Q: Balance the traverse by compass rule. b) Calculate the coordinates of each station.

A: Lattitud and departure signs . N- E: Both positive S-E : Lattitude negative , Departure positive S-W…

Q: 4) What is the Error per angle and Error of closure based on the below sketch for the loop traverse?

Q: Q3): The following data were collected while running a closed traverse ABCDA starting from A toward…

A: Disclaimer Since you have posted a question with multiple sub-parts, we will solve the first three…

Q: ADJUSTMENT. Trace accurately the traverse 15. GRAPHICAL plotted below and perform the reguired…

A: Introduction- The Guide survey is a simple and frequently used method for establishing the relative…

Q: Q5- For the closed looped traverse PQRS below, find:- 1. Closing error and relative accuracy. 2. The…

A: Given Data:PointsEast xNorth yP199.88300.24Q200275R144.02317.03

Q: Q2/B- A rough sketch of the situation is shown in Fig. PABCQP is a closed traverse. Lengths of lines…

Q: Q5) If |BC| = 166.176 m , determine Azimuth (AB),|AB| and coordinates of point C %3D x=906.54m B…

A: coordinates at A=XA,YA=879.94,88.09 and Azimuth =θABB=XB,YB=906.54,253.95 and Azimuth…

Q: Determine the graph and conversion of the following angles. 1. Convert the following azimuth…

Q: With the same problem, what would be the sketch of this data?

A: Given, Closed traverse data To find : Missing bearings

Q: pl P2 89°50' 268° 81°35' | 185°35' 102°10' N 95°5' 80°25' P4 P3 270°30' 90°25' 191°

Q: Given the following tabulated data for a closed traverse, determine the bearings of CD and EA.

Q: Given the following data of a closed traverse. Compute the bearing of line DE

Q: this is not a graded question and please base your answer on the given choices thank you

Q: 2. Traverse data are tabulated as shown. Adjust the lengths and bearing angles to close the…

Concept explainers

Coordinate Geometry of Survey

Coordinate geometry (COGO) is a method of inserting surveying or engineering data into geographic information system (GIS), computer-aided design (CAD), or mapping software. These data can be collected on the proposed construction site using standard surveying techniques and instrumentation or may be taken from existing maps, engineering plans, drawings, or records. Data gathered on the site includes coordinates of points, bearings, and distances between points. The data are noticed and noted through conventional surveying procedures, like a traverse or layout measurement series and it can be either digital or non-digital. The maps and plans are inclusive of boundaries, divisions, and other components, and these features are shown with coordinate values, the lengths, offset distance, and bearings between them.

Question

A
N88 28' 24"E
258.182 M
A traverse from A to H is shown from the
S87* 33' 16"E
5
figure below. Inside the traverse is a
162.867M
1
lot.
a. Adjust the traverse by compass
rule. Tabulate your computation.
b. Calculate
the
coordinates of
station F if station A has N =
3.
s88° 53' 56"W
144.666M
20000.000, E = 20000.000
c. If station F to corner 4 has bearing
117.396 M
161.965 M
and distance equal to N 33° 56' 46"
W and 86.985 m, calculate the
coordinates of all lot corners.
143.069 M
H
N86 33' 16"W
G
N6* 15 27E
204.152M
N3° 12' 25"E
552.815 M
115.385M
S21* 56' 27"E
134.863 M
S37' 45' 45"E
119.958M
$44' 04' 37"w
240.608 M
S6° 34' 12"E
146.178 M
so° 40' 28"E

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

567 24'E 8. Given the following sketch and tabulated data for a closed traverse in which the length of DE and the bearing of EF have not been observed in the field. 852.18 m el 3.0E.SON TA 492.98 m 3..80.90 845.85 m N55 27 W 661.26 m Closing Line Unknown Bearing 1210.50 m Unknown Length $12°17″E
LINE DISTANCE(m) AZIMUTH AB 647.25 306.92 deg. BC 203.03 354.32 deg. CD 720.35 195.53 deg. DE 610.24 104.59 deg. EA 275.13 26.16 deg. Given the obtain data from Traversing. Determine the total area of the closed traverse in Acre.
In a traverse ABCD the angles to the right are measured and the azimuth of the lines PA and DR are (160° - 125°20') respectively. Calculate the azimuth and the quadrantal bearings * for all sides of the traverse 237 10 248 00 119 40 AZ PA=125 20 R 82 30 AZ PA160
Situation 4] From the given data of a closed traverse, The adjusted bearing of BC using compass rule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. iii. iv. Distance, m 368.76 Line Bearing N15°18'E AB BC CD S85046'E S18030W N77035W 645.38 467.86 DA 593.00
A closed traversed has the following data. LINE DISTANCE BEARING AB 185.33 N 43 E BC 258.28 S 67 E CD ? S 38 W DE ? S 81 W EA 150.87 N 27 W The summation of the latitude and departure of the traverse are -26 and 55, respectively. Using COMPASS RULE, determine the follwowing:(Round off into four decimal places)DETERMINE THE CORRECTED LATITUDE OF THE LINE CD.
FROM THE GIVEN DATA OF A CLOSED TRAVERSE, FIND THE ADJUSTED BEARING OF BC AND DA USING COMPASS RULE.
6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and for 15 distances: B umise los A = 38°30' B = 100°38' C = 149°50 Basigns no 11100D = 85°59' AB= 371.006 m BC = 110.222 m CD = 139.872 m DE 103.119 m E = 165°03' EA = 319.860 m +2- 725121 Moto C D unde Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. 201 Az. = 306°31' E FIGURE 6.24 Sketch for Problem 6.16. A
Determine the area of traverse using Double Parallel Distance. Ans: 4,028,975 m2