n Use induction to prove: for any integer n ≥ 1, Σ(6j – 4) = 3n² – n. j=1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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n
- n.
Use induction to prove: for any integer n ≥ 1, Σ(6j − 4) = 3n² -
j=1
Base case
n = 1 (6j - 4) = 2,3n² — n = 2
Inductive step
Assume that for any k ≥ 1, Σ (6j − 4) =
D
OW!
we will prove that (6j − 4) =
-
1
j=
Σ(6j - 4) = Σ(6j — 4) +
(6-4)+
j=
||
j=
||
||
= 3
+
k²+
k²+
By inductive hypothesis
k+
k+
-(k+1)
- (k+1)
Transcribed Image Text:n - n. Use induction to prove: for any integer n ≥ 1, Σ(6j − 4) = 3n² - j=1 Base case n = 1 (6j - 4) = 2,3n² — n = 2 Inductive step Assume that for any k ≥ 1, Σ (6j − 4) = D OW! we will prove that (6j − 4) = - 1 j= Σ(6j - 4) = Σ(6j — 4) + (6-4)+ j= || j= || || = 3 + k²+ k²+ By inductive hypothesis k+ k+ -(k+1) - (k+1)
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