n Use induction to prove: for any integer n ≥ 1, Σ(6j – 4) = 3n² – n. j=1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![n
- n.
Use induction to prove: for any integer n ≥ 1, Σ(6j − 4) = 3n² -
j=1
Base case
n = 1 (6j - 4) = 2,3n² — n = 2
Inductive step
Assume that for any k ≥ 1, Σ (6j − 4) =
D
OW!
we will prove that (6j − 4) =
-
1
j=
Σ(6j - 4) = Σ(6j — 4) +
(6-4)+
j=
||
j=
||
||
= 3
+
k²+
k²+
By inductive hypothesis
k+
k+
-(k+1)
- (k+1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa47fe7e-41f9-4aff-97dd-6182f6f05fcb%2F9570d92e-21b3-45c1-b0ab-48fb739010a1%2F36omb4_processed.png&w=3840&q=75)
Transcribed Image Text:n
- n.
Use induction to prove: for any integer n ≥ 1, Σ(6j − 4) = 3n² -
j=1
Base case
n = 1 (6j - 4) = 2,3n² — n = 2
Inductive step
Assume that for any k ≥ 1, Σ (6j − 4) =
D
OW!
we will prove that (6j − 4) =
-
1
j=
Σ(6j - 4) = Σ(6j — 4) +
(6-4)+
j=
||
j=
||
||
= 3
+
k²+
k²+
By inductive hypothesis
k+
k+
-(k+1)
- (k+1)
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