Please complete the solution to be similar to themost important line. It's the same line I uploaded apicture of you O = ExE..4AAlPlease complete the solution to be similar to themost important line. It's the same line I uploaded apicture of youPOr =Ac.6LoxA.Ac..7%3DLo+ALEr = In(1+ €g)Lo-LfShrinkage percentage %LoSwelling percentage % =4f-40Lo> H,=99.8mm , L,=40mm> A, =W.=40mmForceΔLE=0/ɛAc(N)(mm)320000.6360000.65400000.7440000.75480000,8520000.87560000.9360000640001.07680001.15800001.37840001.47880001.57920001.77960002.07966002.45880002.65860002.8840002.9820003800003.07720003.25 Calculate the parameters for force P=16000 N.Step2b)P16000 N10 MPaA.1600 mm²ΔL0.4= 0.01040Lo10 MPaE=1000 MPa0.010( 40) ( 1600)L,A,Ac=Lo+AL1584. 458 mm?40+0.416000 N10.1 MPаOT=Ac1584.458 mm2&T=ln(1+e)= ln(1+0.010)= 0.00995Calculate the parameters for force P-20000 N.20000 N12.5 MPаA.1600 mm2ΔLE=0.45: 0.011254012.5 MPa0.01125E-1111. 11 MPaL,A,( 40) ( 1600)Ac=Lo+AL1582. 2 mm²%3D40+0.4520000 NOT== 12. 64 MPa1r000

given data A0 = 1600 mm2 L0 = 40 mm

Answered: n to be similar to the most important…

Engineering

Mechanical Engineering

n to be similar to the most important line. It's the same line I uploaded a picture of you

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.

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Please complete the solution to be similar to the most important line. It's the same line I uploaded a picture of you

Calculate the parameters for force P=16000 N.
Step2
b)
P
16000 N
10 MPa
A.
1600 mm²
ΔL
0.4
= 0.010
40
Lo
10 MPa
E=
1000 MPa
0.010
( 40) ( 1600)
L,A,
Ac=
Lo+AL
1584. 458 mm?
40+0.4
16000 N
10.1 MPа
OT=
Ac
1584.458 mm2
&T=ln(1+e)= ln(1+0.010)= 0.00995
Calculate the parameters for force P-20000 N.
20000 N
12.5 MPа
A.
1600 mm2
ΔL
E=
0.45
: 0.01125
40
12.5 MPa
0.01125
E-
1111. 11 MPa
L,A,
( 40) ( 1600)
Ac=
Lo+AL
1582. 2 mm²
%3D
40+0.45
20000 N
OT=
= 12. 64 MPa
1r000

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