Н н Н CH3 c3C ČH3 trans-2-butene CH3 CH3 Н cis-2-butene CA = 0.1CA0 CAO vo- V = 0 A -B V1
How Large Is It?
Consider the liquid phase cis – trans isomerization of 2–butene
which we will write symbolically as
A ⎯⎯→ B
The reaction is first order in A (–rA = kCA) and is carried out in a tubular reactor in which the volumetric flow rate, , is constant, i.e.,v = v0
1. Sketch the concentration profile.
2. Derive an equation relating the reactor volume to the entering and exiting concentrations of A, the rate constant k, and the volumetric flow rate v0.
3. Determine the reactor volume, V1, necessary to reduce the exiting concentration to 10% of the entering concentration, i.e., CA = 0.1CA0, when the volumetric flow rate is 10 dm3/min (i.e., liters/min) and the specific reaction rate,k, is 0.23min.-1
Trending now
This is a popular solution!
Step by step
Solved in 6 steps with 8 images
