Nis the random variable for the number of accidents in a single year. Nfollows thedistribution:Pr(N= n) = 0.9(0.1)"-'n = 1, 2,...X, is the random variable for the claim amount of the ith accident. X, follows thedistribution:g(x,) = 0.01 e 0.01x, x,>0, i= 1, 2,...Let Uand V,, V,... be independent random variables following the uniform distribution on(0, 1). You use the inverse transformation method with U to simulate Nand V, to simulateX, with small values of random numbers corresponding to small values of Nand X,.You are given the following random numbers for the first simulation:uV2V3V40.050.300.220.520.46Calculate the total amount of claims during the year for the first simulation.

Answered: Image /qna-images/answer/42d6db1f-0566-4ac5-b230-9eb8fd09e7e0.jpg

Answered: N is the random variable for the number…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q6. The time to failure of a very sensitive part follows a Weibull distribution with a = 1 hour and B - 1. Calculate the probability that the screen will last exactly for 4 hours? (Assume e=2.718 in your calculation) a f(x; α, β) 3β Xa-1 * e for x > 0; a > 0; B > * elsewhere
The mean and the variance of a binomial distribution with parametersn and p are E(X) -6 and V(X) = 3. Then P(X< 5) = %3D None of these 0.073 0.3872 O 0.1938
A normal distribution has μ = 30 and σ = 5. (a) Find the z score corresponding to x = 25. (Enter an exact number.) (b) Find the z score corresponding to x = 44. (Enter a number.) (c) Find the raw score corresponding to z = −3. (Enter an exact number.) (d) Find the raw score corresponding to z = 1.5. (Enter a number.)
You take a simple random sample of size 25 from a very large population in which the true proportioni p=0.1. Which statement below best describes what you know about the sampling distribution of p? (0.1)(0.9) (a) H,-0.1; o,- the distribution is skewed right. 25 (0.1)(0.9). 25 (b) H,=0.1; o,=. ; the distribution is skewed left. (0.1)(0.9). (c) ,=0.1; o,= the distribution is approximately Normal. %3D 25 (0.1)(0.9) (d) , the distribution is not approximately Normal. 25 =0.1; we cannot use the formula o, (0.1)(0.9) ; the distribution is approximately Normal. 25 (e) =0.1; we cannot use the formula o,
Reaction time is the amount of time it takes to respond to a stimulus, and for automobile drivers, it is an important factor in staying safe while on the road by avoiding rear-end collisions. Reaction times vary from driver to driver and tend to be longer than one might think. A recent study determined that the time for an in-traffic driver to react to a brake signal from standard brake lights can be modeled with a normal distribution having mean value 1.24 seconds and standard deviation of 0.45 seconds. If we let X denote reaction time for automobile drivers, use the appropriate Normal Distribution to determine each of the following. 1. What is the probability that a driver has a reaction time less than 0.6 seconds? 2. Approximately what proportion of drivers have a reaction time more than 2.5 seconds? 3. Within what limits, centered about the mean, would you expect driver reaction times to lie with 95% probability? What are the z-scores for these limits? 4. What is the reaction time…
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roblem 1 If the population parameters are μ = 7 and σ = 1: a) Compute the z score for the lowest (x-4) and highest grade (x=10). (15 pts) -3 b) Compute the proportion of the normal distribution corresponds to z-score values greater than the highest grade. (10 pts) 7 = 7 0 σ = I X = 10 3 3.00
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Continuous of the question: The average time to run the 5K fun run is 24 minutes and stardard deviation is 2.7 minutes. 16 runners are randomly selected to run the 5K fun run. Round all answers to 4 decimal places where possible and assume a normal distribution.

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