n a Cartesian plane, if the position vector of a moving particle is given by ř = xi + yj, then the x and y components of velocity is given by dx dt and dy respectively. On the other hand, the polar components, i.e., the r OP and 0 components of velocity is given by # and r. Using these, prove chat the r component of acceleration is dt ° d²r do fr - r()? dt (10) dt2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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(a) In a Cartesian plane, if the position vector of a moving particle is given
by r = xi + yj, then the x and y components of velocity is given by
and 4 respectively. On the other hand, the polar components, i.e., the r
and 0 components of velocity is given by 4 and re. Using these, prove
dx
dt
dy
that the r component of acceleration is
d²r
do
2
fr
dt2
r(?
(10)
-
dt
(b) A smooth straight thin tube revolves with uniform angular velocity w in
a vertical plane about one end which is fixed. A particle inside the tube is
sliding along the tube with a constant velocity v. At time t = 0, the tube
was horizontal and the particle was at a distance a from the fixed end.
Show that the motion of the particle can be described by the differential
equation
dr
rw? = -g sin wt
(11)
dt?
[Hint: Use formula (10)|
(c) Find the complementary function (CF) and the particular integral (PI)
of the differential equation (11).
Transcribed Image Text:(a) In a Cartesian plane, if the position vector of a moving particle is given by r = xi + yj, then the x and y components of velocity is given by and 4 respectively. On the other hand, the polar components, i.e., the r and 0 components of velocity is given by 4 and re. Using these, prove dx dt dy that the r component of acceleration is d²r do 2 fr dt2 r(? (10) - dt (b) A smooth straight thin tube revolves with uniform angular velocity w in a vertical plane about one end which is fixed. A particle inside the tube is sliding along the tube with a constant velocity v. At time t = 0, the tube was horizontal and the particle was at a distance a from the fixed end. Show that the motion of the particle can be described by the differential equation dr rw? = -g sin wt (11) dt? [Hint: Use formula (10)| (c) Find the complementary function (CF) and the particular integral (PI) of the differential equation (11).
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