The trait for red hair is recessive (r) to the trait for brown hair (R). What is the probability that two parents, one with red hair and one heterozygous for brown hair will have 6 children, 4 with brown hair and 2 with red hair?
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The trait for red hair is recessive (r) to the trait for brown hair (R). What is the probability that two parents, one with red hair and one heterozygous for brown hair will have 6 children, 4 with brown hair and 2 with red hair?
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- Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%Imagine that a couple is planning to have children. The male is heterozygous for Huntington’s disease and homozygous dominant for Tay-Sachs. The female is homozygous recessive for Huntington’s disease and heterozygous for Tay-Sachs. The couple is curious about the possibility and probability of their offspring inheriting Tay-Sachs and/or Huntington’s. For humans, Huntington’s disease is dominant (H) over the “normal” condition (h), and the “normal” condition is dominant (T) over Tay-Sachs (t). Complete a Punnett square for this cross and record the probabilities for genotypes and phenotypes of the offspring as ratios.Red/green colour blindness is a sex-linked trait. Show the Punnett square for a father who is colour blind and a mother who is not colour blind and not a carrier. What are the genotype and phenotype percentages of the possible offspring? Why do they say that such traits “skip a generation?”
- Incomplete dominance is characterized by a cross between homozygous dominant and recessive genes that will result in an intermediate trait assume the following sets of genes is a human being: BB – black-colored pupil HH – straight hair Bb – blue-colored pupil Hh – wavy hair hh – curly hair A husband and wife, BBHH x bbHh, want to know the probability of having a child with a blue-colored pupil and wavy hair. What will you tell them? O There is a ¼ chance that the offspring will have blue-colored pupils and wavy hair. O There is a ½ chance that the offspring will have blue-colored pupils and wavy hair. O There is no chance that the offspring will have blue-colored pupils and wavy hair. O Impossible to determine.The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? Do a cross to determine all potential hitchhiker’s thumb genotypes and phenotypes for the offspring of this man and woman. Is it possible for any offspring of the F1 generation to have hitchhiker’s thumb?In humans, hair color and structure are determined by two independent pairs of genes. The dominant gene T determines dark hair color, and the recessive allele t - light hair; The dominant gene S determines the formation of curly hair, and its recessive allele t - straight hair. What kind of hair will the children have if the mother has light, straight hair, and the father has dark, curly hair (one of the pairs of traits is heterozygous for both parents)?
- in earlobes, attached (A) earlobe is dominant while free (f) earlobe is recessive. - free earlobes with heterozygous dominant for attached earlobes? (percent) - heterozygous for attached earlobes with heterozygous for attached earlobes. (percentage) - Homozygous dominant for attached earlobes with free earlobes. (Answer in percent)Color blindness is a recessive sex linked disorder among humans. A colorblind man has a child with a woman who is a carrier of the disorder. Given the following genotypes: XN= normal vision and Xn = colorblindness, what is the chance of having colorblind daughters? * 100% 50% 25% 75%In rabbits, short hair is dominant (H) and long hair is recessive (h). In percentages, what is the expected outcomeof long and short hair when the parents are heterozygous for this trait?
- Mickey Mouse met the Minnie mouse at a dance. Mickey is heterozygous for his round ear shape, but Minnie has oval-shaped ears. Create a Punnett square to show the possibilities that would result if Mickey and Minnie had children. HINT: Read question #21 (Use E for dominant ande for recessive) 1. List the possible genotypes and phenotypes for their children. 2. What are the chances of a child with a square shape? out of or out of or 3. What are the chances of a child with human shape?A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8My father is homozygous dominant (T) for tall and (B) black hair. My mother is heterozygous recessive (t) and (b) brown hair. What are the possible genotypes and phenotypes? Circle all the genotypes.