MY NOTES Renal Disease ASK YOUR TEACHER The mean serum-creatinine level measured in 15 patients 24 hours after they received a newly proposed antibiotic was 1.1 mg/dL. Ho: You can use SALT, to answer parts of this question. (a) If the mean and standard deviation of serum creatinine in the general population are 1.0 and 0.4 mg/dL, respectively, then, using a significance level of 0.05, test whether the mean serum-creatinine level in this group is different from that of the general population. State the null and alternative hypotheses (in mg/dL). (Enter != for # as needed.) H₁: PRACTICE ANOTHER H=1.0 U>1.0 X X X Find the test statistic. (Round your answer to two decimal places.) 0.97 ✔ Find the rejection region. (Round your answers to two decimal places. If the test is one-sided, enter NONE for the unused region.) test statistic > 0.05 test statistic < NONE State your conclusion. O Fail to reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. Fail to reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. (b) What is the p-value for the test? (Use technology to find the p-value. Round your answer to four decimal places.)

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# Renal Disease Statistical Analysis

### Context

The mean serum-creatinine level measured in 15 patients 24 hours after they received a newly proposed antibiotic was 1.1 mg/dL.

### Statistical Testing

You can use **SALT** to answer parts of this question.

#### (a) Hypothesis Testing

If the mean and standard deviation of serum creatinine in the general population are 1.0 and 0.4 mg/dL, respectively, then, using a significance level of 0.05, test whether the mean serum-creatinine level in this group is different from that of the general population.

1. **State the null and alternative hypotheses (in mg/dL):**

   - Null Hypothesis (\(H_0\)): \( \mu = 1.0 \)
   - Alternative Hypothesis (\(H_1\)): \( \mu > 1.0 \)

   (Note: The question involves correcting marked answers and addressing inaccuracies.)

2. **Find the test statistic:**

   - Calculated Test Statistic: 0.97

3. **Find the rejection region:**

   - Significance level: 0.05

   The correctly marked sections indicate that the test statistic does not exceed the critical value for a one-sided test. Thus, none of the specified rejection criteria were met.

4. **State your conclusion:**

   - **Correct Conclusion:** Fail to reject \(H_0\). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population.

### Further Analysis

#### (b) P-value

To complete the analysis, determine the p-value for the test using technology and round it to four decimal places.

---

This exercise highlights testing a hypothesis concerning serum creatinine levels, addressing concepts like test statistics and rejection regions applicable in biological research contexts.
Transcribed Image Text:# Renal Disease Statistical Analysis ### Context The mean serum-creatinine level measured in 15 patients 24 hours after they received a newly proposed antibiotic was 1.1 mg/dL. ### Statistical Testing You can use **SALT** to answer parts of this question. #### (a) Hypothesis Testing If the mean and standard deviation of serum creatinine in the general population are 1.0 and 0.4 mg/dL, respectively, then, using a significance level of 0.05, test whether the mean serum-creatinine level in this group is different from that of the general population. 1. **State the null and alternative hypotheses (in mg/dL):** - Null Hypothesis (\(H_0\)): \( \mu = 1.0 \) - Alternative Hypothesis (\(H_1\)): \( \mu > 1.0 \) (Note: The question involves correcting marked answers and addressing inaccuracies.) 2. **Find the test statistic:** - Calculated Test Statistic: 0.97 3. **Find the rejection region:** - Significance level: 0.05 The correctly marked sections indicate that the test statistic does not exceed the critical value for a one-sided test. Thus, none of the specified rejection criteria were met. 4. **State your conclusion:** - **Correct Conclusion:** Fail to reject \(H_0\). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. ### Further Analysis #### (b) P-value To complete the analysis, determine the p-value for the test using technology and round it to four decimal places. --- This exercise highlights testing a hypothesis concerning serum creatinine levels, addressing concepts like test statistics and rejection regions applicable in biological research contexts.
### Hypothesis Testing of Serum Creatinine Levels

#### (c) Hypothesis Test

**Given:**
- The sample standard deviation of serum creatinine is 0.7 mg/dL.
- The standard deviation of serum creatinine is not known.

**Task:**
- Perform the hypothesis test with the provided data and report a p-value.

**Test Statistic:**
- Compute and round your answer to two decimal places: `0.55` ✔️

**Using Technology to Report a p-value:**
- Calculate the p-value and round your answer to four decimal places: `p-value = 0.2944` ❌
  - Note: You may have computed the probability of one tail of the distribution. Consider which area of the distribution is appropriate.

**Conclusion Options:**
- **Option 1:** Fail to reject \( H_0 \). There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population.
- **Option 2:** Fail to reject \( H_0 \). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population.
- **Option 3:** Reject \( H_0 \). There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population.
- **Option 4:** Reject \( H_0 \). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. ❌

#### (d) Confidence Interval

**Task:**
- Compute a two-sided 95% confidence interval (CI) for the true mean serum-creatinine level (in mg/dL).

**Result:**
- Interval: `(0.71, 1.49)` ✔️

#### (e) Relation of Confidence Interval to Hypothesis Test

**Question:**
- How does the confidence interval relate to the hypothesis test conclusion?

**Answer:**
- The interval contains the mean for the general population. This supports the conclusion of our test in part (c). ✔️

---

#### Need Help?

- **Option to Read More:** Click the "Read It" button for further assistance.
Transcribed Image Text:### Hypothesis Testing of Serum Creatinine Levels #### (c) Hypothesis Test **Given:** - The sample standard deviation of serum creatinine is 0.7 mg/dL. - The standard deviation of serum creatinine is not known. **Task:** - Perform the hypothesis test with the provided data and report a p-value. **Test Statistic:** - Compute and round your answer to two decimal places: `0.55` ✔️ **Using Technology to Report a p-value:** - Calculate the p-value and round your answer to four decimal places: `p-value = 0.2944` ❌ - Note: You may have computed the probability of one tail of the distribution. Consider which area of the distribution is appropriate. **Conclusion Options:** - **Option 1:** Fail to reject \( H_0 \). There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. - **Option 2:** Fail to reject \( H_0 \). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. - **Option 3:** Reject \( H_0 \). There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. - **Option 4:** Reject \( H_0 \). There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. ❌ #### (d) Confidence Interval **Task:** - Compute a two-sided 95% confidence interval (CI) for the true mean serum-creatinine level (in mg/dL). **Result:** - Interval: `(0.71, 1.49)` ✔️ #### (e) Relation of Confidence Interval to Hypothesis Test **Question:** - How does the confidence interval relate to the hypothesis test conclusion? **Answer:** - The interval contains the mean for the general population. This supports the conclusion of our test in part (c). ✔️ --- #### Need Help? - **Option to Read More:** Click the "Read It" button for further assistance.
Expert Solution
Step 1

As per the Bartleby guildlines we have to solve first three subparts and rest can be reposted....

 

Given that

Sample size=15

Sample mean=1.1

Population mean=1

Population Standard deviation =0.4

We have to find

a... Hypothesis testing .

b..p value 

c..test statistic if population standard deviation is unknown and sample standard deviation =0.7

P value..

 

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