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MY NOTES ASK YOUR TEACHER At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h². Let v(t) be the velocity of the car t hours after 2:00 PM. Then (1/4) - v(0) _ . By the Mean 1/4 - 0 Value Theorem, there is a number c such that 0 < c < 2 . Since with v'(c) = X v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h².

MY NOTES ASK YOUR TEACHER At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h². Let v(t) be the velocity of the car t hours after 2:00 PM. Then (1/4) - v(0) _ . By the Mean 1/4 - 0 Value Theorem, there is a number c such that 0 < c < 2 . Since with v'(c) = X v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h².

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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H MY NOTES ASK YOUR TEACHER At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h². Let v(t) be the velocity of the car t hours after 2:00 PM. Then: v(1/4) v(0) 1/4 - 0 = . By the Mean Value Theorem, there is a number c such that 0 <c< 2 with v'(c) = X v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h². Submit Assignment Save Assignment Progress Home My Assignments +Request Extension Copyright © 1998 - 2022 Cengage Learning, Inc. All Rights Reserved | TERMS OF USE PRIVACY Downloads 4.2 The Mean Value... O Answered: A functi... Daily Paperwork - E... . Since
Transcribed Image Text:H MY NOTES ASK YOUR TEACHER At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h². Let v(t) be the velocity of the car t hours after 2:00 PM. Then: v(1/4) v(0) 1/4 - 0 = . By the Mean Value Theorem, there is a number c such that 0 <c< 2 with v'(c) = X v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h². Submit Assignment Save Assignment Progress Home My Assignments +Request Extension Copyright © 1998 - 2022 Cengage Learning, Inc. All Rights Reserved | TERMS OF USE PRIVACY Downloads 4.2 The Mean Value... O Answered: A functi... Daily Paperwork - E... . Since
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