must for a cond conductor. Com ule: A charge di=
Related questions
Question
Answer all parts of the PHYSICS problem please
Transcribed Image Text:(a) An insulating sphere carries a charge that is spread uniformly throughout its volume. A con-
ducting sphere of the same size carries the same charge, but it is spread over its surface only
with no charge in the interior (as it must for a conductor!) Compare the electric fields outside
the insulator to the field outside the conductor. Compare the electric fields inside the insulator
to the field inside the conductor.
(b) Part (a) is an example of a general rule: A charge distributed through some volume will always
produce an electric field whose value is a continuous function of position as we cross out of the
charge (as we did going from inside to outside of the uniformly charged insulating sphere.) A
charge that is distributed across an area (a thin layer of charge with surface charge density o)
will produce a field whose value is a DIScontinuous function of position, and the discontinuity
is only in the component that is perpendicular to the area and has a value equal to o/e0. Show
that this is true for the cylindrical symmetry and planar symmetry examples we examined (in
other words, check that at r = R, E is continuous for an infinite uniformly charged cylinder and
that it is discontinuous, with the discontinuity as claimed, for an infinite, hollow thin charged
tube and also when we cross an infinite sheet of charge.) You do not need to derive ANY new
result - you may use the results we already have for these as your starting point, so this is not
intended to be long or complicated! HINT for the thin tube: express the charge Q as surface
density times area.
Expert Solution
Step 1
As per rule, allowed to answer first question and post the remaining in the next submission.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
