MSELFtest 23. Suppose that you are given a decision situation with three possible states of nature: 81, 82, and 83. The prior probabilities are P(s₁) = 0.2, P(82) = 0.5, and P(83) = 0.3. With sample information I, P(I | s₁) = 0.1, P(I|s2) = 0.05 , and P(I|83) = 0.2. Compute the revised or posterior probabilities: P(s₁|I), P(82|I), and P(831).
MSELFtest 23. Suppose that you are given a decision situation with three possible states of nature: 81, 82, and 83. The prior probabilities are P(s₁) = 0.2, P(82) = 0.5, and P(83) = 0.3. With sample information I, P(I | s₁) = 0.1, P(I|s2) = 0.05 , and P(I|83) = 0.2. Compute the revised or posterior probabilities: P(s₁|I), P(82|I), and P(831).
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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23) Answer:- Given, The prior probabilities are P(s1) = 0.2 , P(s2) = 0.5 , and P(3) = 0.3 . With sample information I, P(I | s1) = 0.1, P(I | s2) = 0.05 and P(I | s3) = 0.2.
Using formula,
P(B|A) = [P(A|B)*P(A)]÷ [P(A|B)*P(A) ]
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