Mrs. Hill asked her students to express the sum 1+ 3+ 5+ 7+9+...+ 39 using sigma notation. Four different student answers were given. Which student answer is correct? Select one: 37 O a Zk+2) k--1 40 Ob. E«- 1) k-2 39 E(2k – 1) k-1 20 O d. 2(2k - 1) k-1

Q: If N=6+4+3+1+1/3N, then the value of N is?

A:

Q: Evaluate. n=1 2n+4 7n

A:

Q: 7/2 + 3 4/6

A:

Q: 22n+1 3n+1 2.

A:

Q: (-5)2 n (b) En-1 n²,97n 00

A: Part b,

Q: (2x + 1)3/2 (2x + 1)5/2 – -(2x + 1)3/2 = 10 6. 15

A: to solve given equation

Q: Evaluate. (3- 5)² + 4(1 – 5)

A: Given, (3-5)2 + 4(1-5)

Q: The simplification of 7 + 2.7n-1+ ...+2.7²+2 7+2 is 7^2.5 O (4-(7^n)-1)/3 O (3.7^(n+1)-1)/2 O…

A: To simplify the expression 7n+2•7n-1+••••+2•72+2•7+2

Q: In Exercises 1-6, the given set is a basis for a subspace W. Use the Gram- Schmidt process to…

A: From the given basis we find an orthogonal basis of W. Using Gram-Schmidt process:

Q: What is 3/2 * 4!

A:

Q: what is 2/6 + 4/6

A:

Q: A certain virus infects one in every 200 people. A test used to detect the virus in a person is…

A: Let A be the event that the person is infected.Let B be the event that the person tests…

Q: (-10) - (+20) - (-30) + (-40) O -40 O -10 O 20 O -30

A:

Q: can you show how you got 625 for k and L? and how did you get them at $375

A:

Q: 1*10+8*1=?

A: the given expression is: we have to find the value of the given expression.

Q: 8-6*4+10/2=

A: 8-6*4+10/2

Q: (9, -7) (3, 1). Find 吕 ロ师仁 ?

A:

Q: 35. Select each expression that is equivalent to 5(n + 4). O5n + 4 5n + 20 O 15 + 5n + 5 5(n + 3) +5…

A: We have to select expressions that are equivalent to 5(n + 4).

Q: valuate the expression for the given values of the varial -k2 - (4k - 5n)+ 6n; k= -3 andn=-4 or k =…

A: We have to evaluate the expression: -k2-4k-5n+6n when n=-4, k=-3. In this case we need to put the…

Q: -5 4 -2 -7 -8 2.

A:

Q: -2 1/2 + 1 9/10

A:

Q: 16х3 dx 4x2 — 4х + 1

A:

Q: -11/16 + 3/4

A: The given fractions are,

Q: 6. 8x 9 x+3 4

A: To simplify the given expression

Q: +2 2/8=

A: Fraction: 436+228436=276=92228=188=94

Q: S=n2 to find 11+13+..... +801

A: Given: S=n2 To find: The sum of odd numbers starting from 11 up to 801. That is, 11+13+15+…+801

Counting Principles

In statistics, the counting principle can be said to be the concept in which the quantity of an item is determined. There can be a single item, or a group of items, or items that are related to each other. In every possible set of items, the quantity of the possible item groups or their sorting measures can be determined with counting principles.