35. Select each expression that is equivalent to 5(n + 4). O5n + 4 5n + 20 O 15 + 5n + 5 5(n + 3) +5 5n + 54

Q: 6[5+2(9-4)]

A: Consider the given expression.

Q: Find P-9 P+リ) (P-3)

A:

Q: (n+1)! (n-1)! = 10n

A:

Q: (n^2-n)+((n-1)^2-(n-1))+....+(1^2-1) =n(n+1)(2n+1)/6 - n(n+1)/2

A: We shall first derive the formulas for sum of first n natural numbers and sum of squares of first n…

Q: (2n)! – (2n + 1)! (2n)!

A: It is required to find out , 2n! - 2n+1!2n!  For this we use factorial properties.

Q: Find each (n+3)(n+2) (4n 5)(3n + 2) (n+7)(n + 5)

A: Since you have posted multiple subparts we solve the first three subparts for you to get the…

Q: Write the binomial expansion for (x+ 2y)*. (x + 2y)* =D

A:

Q: {21} s² +4 9-1 3 (28+5)³ 2} ₁-55

A:

Q: 3) (n² + 10n+18) ÷ (n+ 5)

A: To divide the following expression.n2+10n+18÷n+5

Q: 16 If X-B (4, p) and P (X=0)=- then P (X=4) 81

A:

Q: 3a + 46° – 5 = 3 (6) +4(2) – 5 ? ||

A: Solution: The objective is to calculate the value

Q: 4x³ dp- x4 + 2

A: ∫4x3x4+2dxwe know tat ddx(x4+2)=4x3Use the common integral:  ∫1udu=lnu∫4x3x4+2dx=ln(x4+2)+C

Q: ´5s²–15s-11) -(s+1)(s–2)³. 34-2s 2. i) Find ii) Evaluate (15(s-5)(s+3).

A: The solution is given as

Q: 16 n+ 3 2: Find the remainder when 5 + 2 (14!) is divided by 17.

A:

Q: 8+2z+6(z-1)

A: Given,

Q: The expansion of the term (2x -) 16+x- 6x? + 16x³ – 16x* 16 16 – 64x + 96x2 – 64x3 + 16x* 1 -x + 6x2…

A: In this question we have to find the expression which we can find out by using the binomial theorem

Q: K(t)= 20+ 11t K(5)3D %D

A: We are given k(t)= -20 +11t

Q: 3[2+4(5+2*3)]

A:

Q: o 5 (10 - 2 3) + 8

A:

Q: Use the Binomial Theorem to expand and simplify the expression 2(x- 3)4 + 5(x - 3)² Select one: O a.…

A:

Q: 5 =5 Hence, 6"-1 is divisible by 5 is (10.). for n=1 Part 2: Assume that 6" - 1 is divisible by 5…

A:

Q: 2) (n²-n-29) (n-6)

A: Please refer to the image below

Q: 5 (4k + 3) k 1

A: Given,

Q: 4) (-7k+10 ) (k- 1)

A:

Q: Prove (n + 6)² – (n + 2)² is always a multiple of 8. (Use direct proof.)

A:

Q: How many zeroes does 188! end with?

A: count number of five's in 188, 5*2=10 . Divide 188 and write quotient again divide quotient again by…

Q: 2(n-3)+n(2-n)=2-n2

A:

Q: 3/2+8(1)

A: Solve the expression as follows.

Q: -n 2n+5

A: We have given a series.

Q: +3 dx 82x +3 (A) 2in(8) +C 82x +3 B +C In(8)2 82x+3 + C In(64) 42x +3 In(8) D - + C

A:

Q: an =4(n+3)!  write first four terms

A: Using given sequence ,

Counting Principles

In statistics, the counting principle can be said to be the concept in which the quantity of an item is determined. There can be a single item, or a group of items, or items that are related to each other. In every possible set of items, the quantity of the possible item groups or their sorting measures can be determined with counting principles.