Mr. Vincent has discovered the following new elements with their respective molar masses and charge: Element Chemical Symbol Molar Mass (in g/mol) Oxidation Number (Charge) Pestingyawa Pe 10 g/mol +2 Tiburcium T 100 g/mol +4 Mamshie Ma 50 g/mol -2 Ludine Lu 20 g/mol -4 100 g of Pestingyawa Mamshide (PeMa) reacted with 60 g Tiburcium Ludide (TLu) via double displacement reaction, forming Pestingyawa Ludide and Tiburcium Mamshide. If the Percent Yield of Tiburcium Mamshide is only 50%, what is its actual yield (in grams)?
Mr. Vincent has discovered the following new elements with their respective molar masses and charge: Element Chemical Symbol Molar Mass (in g/mol) Oxidation Number (Charge) Pestingyawa Pe 10 g/mol +2 Tiburcium T 100 g/mol +4 Mamshie Ma 50 g/mol -2 Ludine Lu 20 g/mol -4 100 g of Pestingyawa Mamshide (PeMa) reacted with 60 g Tiburcium Ludide (TLu) via double displacement reaction, forming Pestingyawa Ludide and Tiburcium Mamshide. If the Percent Yield of Tiburcium Mamshide is only 50%, what is its actual yield (in grams)?
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter4: Stoichiometry Of Chemical Reactions
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Mr. Vincent has discovered the following new elements with their respective molar masses and charge:
100 g of Pestingyawa Mamshide (PeMa) reacted with 60 g Tiburcium Ludide (TLu) via double displacement reaction, forming Pestingyawa Ludide and Tiburcium Mamshide. If the Percent Yield of Tiburcium Mamshide is only 50%, what is its actual yield (in grams)? |
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