Mr. Usabal uses two charged parallel plates and try to calculate the potential energy between the plates. The separation between the plates is 5 cm and the magnitude of the electric field between the plates is 650 volt/meter. What is the change in potential energy of the proton when accelerated from the positively charged plate to the negatively charged plate.

Q: Two 2.2-cm-diameter-disks spaced 1.7 mm apart form a parallel-plate capacitor. The electric field…

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Q: A pair of oppositely charged, parallel plates are separated by 5.30 mm. A potential difference of…

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Q: In a beam of protons, each proton has a speed of 4.90x 105m/s. The beam enters a region between…

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Q: The two parallel plates shown below create a uniform electric field. A proton is travelling due east…

A: The potential difference V=V1-V2=825-125=700 Volts

Q: A +3.6 µC is placed at (0.0 cm, 2.6 cm) and a -4.8 µC charge is placed at (3.1 cm, 0.0 cm) as shown…

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Q: A computer monitor creates an image by accelerating electrons between parallel plates. If the…

A: Given, A computer monitor creates an image by accelerating electrons between parallel plates.…

Q: Consider the parallel-plate capacitor shown in the figure. The plate separation is 6.6 mm and the…

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Q: Four identical charged particles (q = +17.0 µC) are located on the corners of a rectangle as shown…

A: Given The magnitude of the charge is q = 17 µC = 17 x 10-6 C. The width of the rectangle is W = 12…

Q: A charged particle Qo=1 nC is placed on the positively charged plate of a capacitor, as in the…

A: Here given that:Total charge of the plate 10mC.The value Q₀ = 1nC. The value of area of the plate 1…

Q: A 2.4x10 -9 C charge is initially traveling at a speed of 1.0 x 10 5 m/s in a parallel plate setup.…

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Q: Oppositely charged parallel plates are separated by 6.06 mm. A potential difference of 600 V exists…

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Q: Two particles with Q1 = 48 µC and Q2 = 91 µC are initially separated by a distance of 2.2 m and then…

A: Given : Charges Q1 = 48 µC = 48 x 10-6 C and Q2 = 91 µC  = 91 x 10-6 C Distance d1 = 2.2m ; Final…

Q: The separation distance between the two plates of a parallel plate capacitor is 2.72 cm. An electron…

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Q: Consider the parallel-plate capacitor shown in the figure. The plate separation is 2.3 mm and the…

A: Solution:-             Given,           d=2.3mm,E=18N/C        electric field will be…

Q: Some forms of tumors can be treated using proton therapy. The physics idea behind this biomedical…

A: We would use conservation of energy. As  Decrease in potential energy of proton=increase in KE of…

Q: Oppositely charged parallel plates are separated by 5.78 mm. A potential difference of 600 V exists…

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Q: proton is launched with a speed of 10000 km/s towards uniformly charged planar sheet of charge,…

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Q: H proton is released from rest in a uniform electric field that has a magnitude of 30000v/m. The…

A: Given  E = 30,000 V/m X = 0.5 m

Q: The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. THe potential…

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Q: Oppositely charged parallel plates are separated by 6.12 mm. A potential difference of 600 V exists…

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Q: The electrons in a CRT are accelerated through a potential difference of 30kV. Do the electrons move…

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Q: Suppose an electron (q=-e=-1.6x10^-19 C, m=9.1x10^-31kg) is accelerated from rest through a…

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Q: Four identical charged particles (g = +13.0 pC) are located on the comers of a rectangle as shown in…

A: Given data: The magnitude of the charges is, q=13 μC The length of the rectangle is, L= 55 cm=0.55 m…

Q: The plates of a parallel plate capacitor are 2.5 cm apart. Between the plates they create a uni-…

A: Given value--- Separation between plate r = 2.5 cm = 0.025 m . electric field = 525 N/C  We have…

Q: Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential…

A: 1) Distance between the plates d=2cm=0.02m V=195V  Electric field between plates is E=V…

Q: e on an electron between th

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Q: Four identical charged particles (q=+12.0 µC) are located on the corners of a rectangle as shown in…

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Q: Consider the parallel-plate capacitor shown in the included image. The plate separation is d = 2.2…

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Q: The electric potential V in the space between two flat parallel plates 1 and 2 is given (in volts)…

A: Given, The electric potential V in the space between two flat parallel plates 1 and 2 is given (in…

Q: Oppositely charged parallel plates are separated by 5.56 mm. A potential difference of 640 V exists…

A: Given data: Distance between plates (d) = 5.56 mm Potential difference (ΔV) = 640 V

Q: Oppositely charged parallel plates are separated by 6.28 mm. A potential difference of 600 V exists…

A: Given values:Potential difference between the plates, V = 600 VDistance between the plates, d = 6.28…

Q: A parallel plate capacitor is formed of two 10 cm × 10 cm plates spaced 1 cm apart. The plates are…

A: Given  Charge on positive plate is 1nC  Charge on negative plate is -1nC. Q = 1.67*10-19C m =…

Q: A pair of oppositely charged, parallel plates are separated by 3.95 mm. A potential difference of…

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Q: A proton enters a pair of charged parallel plates (which we call a capacitor) traveling to the right…

A: Here initial horizontal velocity of proton,u=1.276×10-5m/s And initial vertical velocity ,u'= 0m/s…

Q: Four identical charged particles (g = +20.0 μC) are located on the corners of a rectangle as shown…

A: We are given 4 charges which are identical. We are also given value of this charge. We have to find…

Q: wo 2.2-cm-diameter-disks spaced 1.9 mm apart form a parallel-plate capacitor. The electric field…

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Q: Oppositely charged parallel plates are separated by 5.35 mm. A potential difference of 500 V exists…

A: Given: The separation between plates is 5.35 mm. The potential difference is 500 V.

Q: The electric potential difference between two infinite, parallel metal plates is V. If the plates…

A: Let the electric field is denoted by E and the separation of plates is denoted by L.

Q: The potential difference between two parallel plates is 598 V. An alpha particle with mass of…

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Q: A parallel plate capacitor has capacitance C0 = 15.0 pF when there is air between the plates. The…

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Q: Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential…

A: Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first…

Q: Oppositely charged parallel plates are separated by 4.97 mm. A potential difference of 600 V exists…

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Q: To move a charged particle through an electric potential difference of 2.0x10-6 V requires 4.8x10-6…

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Q: Two flat, parallel plates have radii r = 0.10 m and are d = 0.20 cm apart. The potential difference…

A: Given data:   Distance (d) = 0.20 cm Potential difference (V) = 180 V Required: Electric field (E)

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.