mponent form, at the point, P in the diagram below due to the stationary point charges, q1 and q2, where q1 = -2.00 μC and q2 = +1.00 μC. (Assume that k = 9.0 x 109 Nm2/C2)   a. Ex = 8.2 x 107 N/C; Ey = -3.6x 107  N/C   b. Ex = -4.1 x 105 N/C; Ey = -3.6 x 105 N/C      c. Ex  = -4.1 x 107 N/C; Ey = -3.6 x 107 N/C   d. Ex = 6.7 x 105 N/C; Ey = 8.9 x 105 N/C

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Find the electric field, in rectangular component form, at the point, P in the diagram below due to the stationary point charges, q1 and q2, where q= -2.00 μC and q2 = +1.00 μC. (Assume that k = 9.0 x 109 Nm2/C2)

  a.

Ex = 8.2 x 107 N/C; Ey = -3.6x 107  N/C

  b.

Ex = -4.1 x 105 N/C; Ey = -3.6 x 105 N/C   

  c.

Ex  = -4.1 x 107 N/C; Ey = -3.6 x 107 N/C

  d.

Ex = 6.7 x 105 N/C; Ey = 8.9 x 105 N/C

  e.

Ex  = -5.0 x 105 N/C ;  Ey = 4.0 x 105 N/C

OP
112 cm
92
5.0 cm
Transcribed Image Text:OP 112 cm 92 5.0 cm
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