3. In the following system: q1 = +8.0 µC, q2 = -6.00 µC, q3 = -10.0 µC. 92 6m q1 8m q3 a) Find the force on charge 3 due to charge 1, F13 . b) Find the force on charge 3 due to charge 2, F23 . c) Find the resultant force on charge 3, Fres . and its direction (angle Y)
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- Please assist with this question please. Thank youA charge q₁ equal to 0.600 μC is at the origin, and a second charge 92 equal to 0.900 μC is on the x axis at 5.00 cm. 1) Find the force (magnitude and direction) that 0.600-μC charge exerts on 0.900-μC charge. Enter a positive value if the force acts in the +x direction and a negative value if the force acts in the - x direction. (Express your answer to three significant figures.) Submit N 2) Find the force (magnitude and direction) that 0.900-μC charge exerts on 0.600-μC charge. Enter a positive value if the force acts in the +x direction and a negative value if the force acts in the - x direction. (Express your answer to three significant figures.) NJust need #7, but need values from #6.
- 2. Three-point charges q. (+2.0µC), q2 (–1.0µC) and q2 (+3.0µC) are placed in vacuum as shown in the figure. Find the magnitude and direction of the force on charge q3 due to charges qı and q2. 3.0ст 300 6.0cm3. A hollow, conducting sphere is initially uncharged. A positive charge, +9₁, is placed inside the sphere, as shown in the figure below. Then, a second positive charge, +q2, is placed near the sphere but outside it. Which of the following statements describes the net electric force on each charge? +9₂ A. There is a net electric force on +91 but not on +92. B. Both charges are acted on by a net electric force with the same magnitude and in the same direction. C. Both charges are acted on by a net electric force with the same magnitude but in opposite directions. D. There is a net electric force on +q2 but not on +9₁.A charge +q is placed at x = 0 and a charge +4q is placed at x = 5 units. Where, along the x-axis is the net force on a charge Q equal to zero?a). x = 1.27 unitsb). x = 1.52 unitsc).x = 1.67 unitsd). x = 1.21 units e). x= 1.48 units
- Criterion A: Knowing and understanding i. state scientific knowledge. (Max. 2 points) Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The force between them is 2.31 × 10-³ N. Calculate the distance between them (3SF). 1 Qq F 4TE0 p2 x10-3 N = 8.9875 × 10° N m² C-²×( x10-7 C× |x10-5 C) ÷r² 2.31 x 10-3 N = 8.9875 × 10° N m² C-2x( x10-12 C²) ÷r2 V((8.9875 × 10° N m? C-²× ×10-12 C²) ÷ x10-³ N) r = ||#2a. Determine the magnitude of the force between two point charges, Q₁ = -650e located at (-4.60 cm, +3.10 cm) and Q2 = -458e located at (+2.50 cm, -7.60 cm). Give your answer in the form "a.bc x 10^ N". Note that e is the fundamental electric charge. 650e is simply 650 x e (the fundamental electric charge). similarly 458e is simply 458 x e (the fundamental electric charge). (Please type answer no write by hend)