Two small charged objects have charges of Q = -5.77 × 10-7 C and q = -1.23 × 10-5 C. The force between them is 2.31 × 10¬³ N. %3D Calculate the distance between them (3SF). Qq F = 4πεο p2 x10-3 N 8.9875 x 10° N m² C-²×( ×10-7 Cx x10-5 C) ÷r² 2.31 x 10-3 N 8.9875 × 10° N m² C-²×( ]x10-12 C³) ÷r² = v((8.9875 × 10º N m² C-²×[ |x10-12 C²) ÷ |×10-³ N) r =
Two small charged objects have charges of Q = -5.77 × 10-7 C and q = -1.23 × 10-5 C. The force between them is 2.31 × 10¬³ N. %3D Calculate the distance between them (3SF). Qq F = 4πεο p2 x10-3 N 8.9875 x 10° N m² C-²×( ×10-7 Cx x10-5 C) ÷r² 2.31 x 10-3 N 8.9875 × 10° N m² C-²×( ]x10-12 C³) ÷r² = v((8.9875 × 10º N m² C-²×[ |x10-12 C²) ÷ |×10-³ N) r =
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Criterion A: Knowing and understanding
i. state scientific knowledge. (Max. 2 points)
Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The
force between them is 2.31 × 10-³ N.
Calculate the distance between them (3SF).
1
Qq
F
4TE0
p2
x10-3 N = 8.9875 × 10° N m² C-²×(
x10-7 C×
|x10-5 C) ÷r²
2.31 x 10-3 N = 8.9875 × 10° N m² C-2x(
x10-12 C²) ÷r2
V((8.9875 × 10° N m? C-²×
×10-12 C²) ÷
x10-³ N)
r =
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01479f5b-dc96-4658-bea6-d1662c48121b%2Ff6fa9930-b1b4-4885-bb34-89600601114e%2Fuhwou13_processed.png&w=3840&q=75)
Transcribed Image Text:Criterion A: Knowing and understanding
i. state scientific knowledge. (Max. 2 points)
Two small charged objects have charges of Q = -5.77 × 10-7 C and q = –1.23 × 10¬5 C. The
force between them is 2.31 × 10-³ N.
Calculate the distance between them (3SF).
1
Qq
F
4TE0
p2
x10-3 N = 8.9875 × 10° N m² C-²×(
x10-7 C×
|x10-5 C) ÷r²
2.31 x 10-3 N = 8.9875 × 10° N m² C-2x(
x10-12 C²) ÷r2
V((8.9875 × 10° N m? C-²×
×10-12 C²) ÷
x10-³ N)
r =
||
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