Moviegoers An average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 47 moviegoers from a large university revealed that the average number of movies seen per person was 9.5. The population standard deviation is 3.2 movies. At the 0.02 level of significance, can it be concluded that this represents a difference from the national average? Use a graphing calculator. Part: 0/ 4 Part 1 of 4 (a) State the hypotheses and identify the claim. Ho: (Choose one) ▼ ロ=ロ H : (Choose one) ▼ ロロ This hypothesis test is a (Choose one) v test.

Moviegoers An average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 47 moviegoers from a large university revealed that the average number of movies seen per person was 9.5. The population standard deviation is 3.2 movies. At the 0.02 level of significance, can it be concluded that this represents a difference from the national average? Use a graphing calculator. Part: 0/ 4 Part 1 of 4 (a) State the hypotheses and identify the claim. Ho: (Choose one) ▼ ロ=ロ H : (Choose one) ▼ ロロ This hypothesis test is a (Choose one) v test.

Name: Moviegoers An average "moviegoer" sees 8.5 movies a year. A moviegoer
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Moviegoers An average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-monthperiod. A random sample of 47 moviegoers from a large university revealed that the average number of m

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The speed of cars on a specific road is normally distributed with a mean of 54 mph and a standard deviation of 3. The top 2.5% of cars are traveling at at least what mph?
Average adult Americans are about one inch taller but nearly a whopping 25 pounds heavier than they were in 1960, according to a report from the Centers for Disease Control and Prevention (CDC). City A is considered one of America's healthiest cities. Is the weight gain since 1960 similar in city A? A sample of n=25 adults suggested a mean increase of 22 pounds with a standard deviation of 9.4 pounds. Is City A significantly different in terms of weight gain since 1960? Complete and interpret 5 step hypothesis testing by hand at a 5% level of significance using a Z-test. Show each step and your work.
Consider a normally distributed population with a mean of 196 and a standard deviation of 20. Find the value from this population that gives the 0.195 percentile. (Please round your answer to one decimal place, e.g. 0.6.)
A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
According to one study, the average hours of sleep on a weeknight for men was 6.9 hours with a standard deviation of 1.5 hours. These hours are normally distributed. c. Find the proportion of men who sleep between 6-8 hours per night. d. Find the number of hours that represents the 90th percentile.
Suppose there is a city where the mean cost per month of a one-bedroom apartment is $1,500, with a standard deviation of $250. Approximately what percentage of one-bedroom apartments in the city cost between $750 and $1,000?
Suppose the mean number of candies in a standard vending machine bag is 47.6 with a standard deviation of 1.3 . assume that the number of candies is normally distributed what percentage of bags have less than 45 candies?
In the class of 2019, more than 1.6 million students took the SAT. The distribution of scores on the math section (out of 800) is approximately normal with a mean of 528 and standard deviation of 117. What proportion of students earned scores between 500 and 600 on the SAT math test?
It is believed that nearsightedness affects 14% of children in a certain region. A school district tests the vision of 180 incoming kindergarten children. How many would be expected to be nearsighted? What is the standard deviation for the number of nearsighted children in such a group? You may assume that the children are independent of each other. The mean is? and the standard deviation is?
A parenting magazine reports that the average amount of wireless data used by teenagers each month is 5 Gb. For her science fair project, Ella sets out to prove the magazine wrong. She claims that the mean among teenagers in her area is less than reported. Ella collects information from a simple random sample of 25 teenagers at her high school, and calculates a mean of 4.7 Gb per month with a standard deviation of 0.9 Gb per month. Assume that the population distribution is approximately normal. Test Ella's claim at the 0.01 level of significance. Step 3 of 3: Draw a conclusion and interpret the decision. E Tables E Keypad Answer Keyboard Shortcuts We reject the null hypothesis and conclude that there is sufficient evidence at a 0.01 level of significance that the average amount of wireless data used by teenagers each month is less than 5 Gb. We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 0.01 level of significance that the average amount of…
A parenting magazine reports that the average amount of wireless data used by teenagers each month is 10 Gb. For her science fair project, Ella sets out to prove the magazine wrong. She claims that the mean among teenagers in her area is less than reported. Ella collects information from a simple random sample of 16 teenagers at her high school, and calculates a mean of 9.1 Gb per month with a standard deviation of 1.3 Gb per month. Assume that the population distribution is approximately normal. Test Ella's claim at the 0.05 level of significance. Step 3 of 3: Draw a conclusion and interpret the decision.