Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 8 ounces. a. The process standard deviation is 0.15 ounces, and the process control is set at plus or minus 1.6 standard deviations. Units with weights less than 7.76 or greater than 8.24 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)? In a production run of 1000 parts, how many defects would be found (round to the nearest whole number)? b. Through process design improvements, the process standard deviation can be reduced to 0.09 ounces. Assume the process control remains the same, with weights less than 7.76 or greater than 8.24 ounces being classified as defects. What is the probability of a defect (round to 4 decimals; if necessary)? In a production run of 1000 parts, how many defects would be found (to the nearest whole number)? c. What is the advantage of reducing process variation, thereby causing a problem limits to be at a greater number of standard deviations from the mean? It can substantially reduce the number of defects

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 8 ounces. a. The process standard deviation is 0.15 ounces, and the process control is set at plus or minus 1.6 standard deviations. Units with weights less than 7.76 or greater than 8.24 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)? In a production run of 1000 parts, how many defects would be found (round to the nearest whole number)? b. Through process design improvements, the process standard deviation can be reduced to 0.09 ounces. Assume the process control remains the same, with weights less than 7.76 or greater than 8.24 ounces being classified as defects. What is the probability of a defect (round to 4 decimals; if necessary)? In a production run of 1000 parts, how many defects would be found (to the nearest whole number)? c. What is the advantage of reducing process variation, thereby causing a problem limits to be at a greater number of standard deviations from the mean? It can substantially reduce the number of defects

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Suppose that the distance of fly balls hit to the outfleld (in baseball) is normally distributed…

A: X follows a Normal distribution with mean = 257 and S.D = 44 Then z=(x-mean)/SD = (x-257)/44…

Q: he lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation…

Q: The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation…

A: Refer Standard normal table/Z-table to find the probability of z=2.80.

Q: Assume that a vending machine dispenses coffee in amounts that vary uniformly between 7.4 and 8.2…

Q: Exercise 1: The weight of a random scone sold by your favorite bakery has a mean of 105g I a…

A: Given: μ = 105 σ = 5 Formula Used: Z-score= X-μσn

Q: Please help answering this one:

A: a) Calculating the probability: The production process produces items with mean 13 and standard…

Q: The weight of a small Starbucks coffee is a normally distributed random variable with the a mean of…

A: From the given information we find the solution for given problem.

Q: The distance travelled to work by the employees of PUP may be modelled by a normal distribution with…

A: Answer:- Given the distance traveled to work by the employees of PUP may be modeled by a normal…

Q: A florist makes deliveries between 1:00 pm and 5:00 pm daily. Assume delivery times follow the…

A: In a continuous uniform distribution, the two parameters are the minimum value (a) and the maximum…

Q: Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed…

A: Let X = distance in feet for a fly ball. Use excel formula "=NORM.S.INV(0.8416)" to find the…

Q: The process standard deviation is 0.12, and the process control is set at plus or minus 2.5 standard…

A: Given,population mean, .a. b. To answer three sub-parts

Q: The final exam scores in a statistics class were normally distributed with a mean of 63 and a…

Q: d. What is the probability that average yield for 10 days is at most 800 tons? e. What is the…

Q: Let x be a ramdom variable that represents the IQ score of an adult. Then x has a normal…

A: The mean of the data is 100. The standard deviation of the data is 25.

Q: The lengths of pregnancies are normally distributed with a mean of 266 days and a standard…

Q: The weekly demand for Baked Lay's potato chips at a certain Subway sandwich shop is a normally…

A: The question is about normal distribution.Given :Population mean weekly demand ( ) = 450Population…

Q: Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed…

A: Given , Mean,μ =267standard deviation,σ=45using formula,Z-score = x-μσ

Q: a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is…

A: Given Data Population Mean,μ = 269 Population Standard Deviation,σ = 15

Q: The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation…

A: Given,mean(μ)=267standard deviation(σ)=15

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

Q: 5. The heights of NBA basketball players closely follow a Normal distribution with a mean of u = 79…

A: Z-Score: It is a dimensionless quantity that is used to indicate the signed, fractional,…

Q: The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation…

A: The normal distribution is the bell shaped distribution which is centred at the mean. This is also…

Q: Motorola used the normal distribution to determine the probability of defects expected in a…

A: The mean is 11.

Q: Suppose that the walking step lengths of adults are normally distributed with a mean of 2.4 feet and…

Q: In a certain region, the mean annual salary for electricians is $58,650. Let x be a random variable…

A: According to the given information, we have Sample mean = 58650 Sample size = 50 Standard deviation…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process.
Assume a production process produces items with a mean weight of 8 ounces.
a. The process standard deviation is 0.15 ounces, and the process control is set at plus or minus 1.6 standard deviations. Units with weights less
than 7.76 or greater than 8.24 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)?
In a production run of 1000 parts, how many defects would be found (round to the nearest whole number)?
b. Through process design improvements, the process standard deviation can be reduced to 0.09 ounces. Assume the process control remains
the same, with weights less than 7.76 or greater than 8.24 ounces being classified as defects. What is the probability of a defect (round to 4
decimals; if necessary)?
In a production run of 1000 parts, how many defects would be found (to the nearest whole number)?
c. What is the advantage of reducing process variation, thereby causing a problem limits to be at a greater number of standard deviations from
the mean?
It can substantially reduce the number of defects

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 27 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 270 feet and a standard deviation of 42 feet. Let X be the distance in feet for a fly ball. a. What is the distribution of X? X N( b. Find the probability that a randomly hit fly ball travels less than 302 feet. Round to 4 decímal places. c. Find the 90th percentile for the distribution of distance of fly balls. Round to 2 decimal places. feet
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 5. Suppose 100 golfers played the course today. Find the probability that the average score of the 100 golfers exceeded 62. Round to four decimal places. O A. 0.1293 B. 0.3707 O C. 0.4772 O D. 0.0228
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 268 feet and a standard deviation of 43 feet. Let X be the distance in feet for a fly ball. a. What is the distribution of X? X - N( b. Find the probability that a randomly hit fly ball travels less than 219 feet. Round to 4 decimal places. c. Find the 75th percentile for the distribution of distance of fly balls. Round to 2 decimal places. feet
the heights of 18-year old men are approximately normally distributed with a mean of U= 68 inches and a standard deviation of O=3. what is the probability that an 18-year-old mean selected at random is less than 65 inches tall. a .8413 b .1587 c .1389 d .8765
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 420 grams and a standard deviation of 24 grams. Find the weight that corresponds to each event. a. highest 20 percent b. middle 60 percent c. highest 80 percent d. lowest 15 percent
The lengths of pregnancies are normally distributed with a mean of 268days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the lowest 2%, then the baby is premature. Find the length that separates premature babies from those who are not premature. a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as needed.) b. Babies who are born on or before____days are considered premature. (Round to the nearest integer as needed.)
1) The mean and standard deviation of a population are 200 and 20, respectively.The probability of selecting one data value less than 190 is ____ %. (Round answer to the nearest percent (whole number). Do not write the % sign.) 2) A. C. Neilsen reported that children between the ages of 2 and 5 watch an average of 25 hours of television per week. Assume the variable is normally distributed and the standard deviation is 3 hours.If 20 children between the ages of 2 and 5 are randomly selected, the number of children in the sample who watch at least 25.2 hours of television is? Give answer to the nearest whole number, not a percent. 3) A. C. Neilsen reported that children between the ages of 2 and 5 watch an average of 25 hours of television per week. Assume the variable is normally distributed and the standard deviation is 3 hours.If 20 children between the ages of 2 and 5 are randomly selected, the number of children in the sample who watch at most 22.5 hours of television is? . Give…
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the lowest 3%,then the baby is premature. Find the length that separates premature babies from those who are not premature.