mong wormen and high school gini States 2011). MMWR 2013;62:pg 9-13. http://www.cdc.gov/mmwr/pdf/wk/mm6201.pdf The article referenced says that when women aged 25-34 binge drink they have on average 7.2 drinks. I'm wondering if women in Laramie are different than the national average. Assume the standard deviation is 0.42 drinks. I sample 9 women who have done binge drinking, and their average is 5.1 drinks. Can I say at the 0.05 significance level that the average is not equal to 7.27 Hoi- 5.1 HA 5.1 Ho:x - 7.2 HA:x + 7.2 Ho: 7.2 HAH = 7.2 Ho: 5.1 Ho:x 7.2 HA:X = 7.2 Hoi- 7.2 HAH 7.2 HA:- 5.1 P-value ODo not answer until you choose an a ODo not answer until you choose an a You cannot answer this until you choose an a O You cannot answer this until you choose an a

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Source: Centers for Disease Control and Prevention. [Vital Signs: binge Drinking among women and high school girls - United
States 2011]. MMWR 2013;62:pg 9-13. http://www.cdc.gov/mmwr/pdf/wk/mm6201.pdf
The article referenced says that when women aged 25-34 binge drink they have on average 7.2 drinks. I'm wondering if women in
Laramie are different than the national average. Assume the standard deviation is 0.42 drinks. I sample 9 women who have done
binge drinking, and their average is 5.1 drinks. Can I say at the 0.05 significance level that the average is not equal to 7.2?
Hg:X = 7.2
HA:X + 7.2
Ho:x + 7.2
HAix = 7.2
Ho:u - 5.1
Ho: = 7.2
Họ:* 5.1
Ho:u + 7.2
HA 5.1
HA:H 7.2
HA:H - 5.1
HA:H - 7.2
P-value
ODo not answer until you choose an a
ODo not answer until you choose an a
You cannot answer this until you choose an a
O You cannot answer this until you choose an a
Transcribed Image Text:Source: Centers for Disease Control and Prevention. [Vital Signs: binge Drinking among women and high school girls - United States 2011]. MMWR 2013;62:pg 9-13. http://www.cdc.gov/mmwr/pdf/wk/mm6201.pdf The article referenced says that when women aged 25-34 binge drink they have on average 7.2 drinks. I'm wondering if women in Laramie are different than the national average. Assume the standard deviation is 0.42 drinks. I sample 9 women who have done binge drinking, and their average is 5.1 drinks. Can I say at the 0.05 significance level that the average is not equal to 7.2? Hg:X = 7.2 HA:X + 7.2 Ho:x + 7.2 HAix = 7.2 Ho:u - 5.1 Ho: = 7.2 Họ:* 5.1 Ho:u + 7.2 HA 5.1 HA:H 7.2 HA:H - 5.1 HA:H - 7.2 P-value ODo not answer until you choose an a ODo not answer until you choose an a You cannot answer this until you choose an a O You cannot answer this until you choose an a
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