Molarity of titrant (NaOH): 0.4550 M HC2H3O2 (aq) + NaOH (aq) → NaC2H3O2 (aq) + H2O (l) Trial # First Second Third Fourth Initial buret reading 0.15 mL 2.43 mL 1.32 mL 0.58 mL Final buret reading 18.62 mL 20.87 mL 20.03 mL 19.14 mL Volume of titrant used 18.47 mL 18.44 mL 18.71 mL 18.56 mL 4) Calculate the molarity of the acetic acid in the vinegar solution (Show your work). use FW for moles-->grams acetic acid. Molarity acetic acid = _____________ M 5) Calculate the weight % of acetic acid in the vinegar. How does this compare with the % listed on the label (5.00%)? (For this calculation assume that density of vinegar is 1.03 g/mL and of course, show your work). Weight % = ___________ 6) If you didn’t get the same weight % of acetic acid as listed on the vinegar label (5.00 %), what are two things (be specific) that could’ve happened during the experiment that could explain the variation from the expected weight %? To do this you need the mass of the acetic acid and the mass of the vinegar you are provided the density of the vinegar. You can use the density for volume-->grams vinegar
Molarity of titrant (NaOH): 0.4550 M
HC2H3O2 (aq) + NaOH (aq) → NaC2H3O2 (aq) + H2O (l)
|
Trial # |
First |
Second |
Third |
Fourth |
|
Initial buret reading |
0.15 mL |
2.43 mL |
1.32 mL |
0.58 mL |
|
Final buret reading |
18.62 mL |
20.87 mL |
20.03 mL |
19.14 mL |
|
Volume of titrant used |
18.47 mL |
18.44 mL |
18.71 mL |
18.56 mL |
4) Calculate the molarity of the acetic acid in the vinegar solution (Show your work).
use FW for moles-->grams acetic acid.
Molarity acetic acid = _____________ M
5) Calculate the weight % of acetic acid in the vinegar. How does this compare with the % listed on the label (5.00%)? (For this calculation assume that density of vinegar is 1.03 g/mL and of course, show your work).
Weight % = ___________
6) If you didn’t get the same weight % of acetic acid as listed on the vinegar label (5.00 %), what are two things (be specific) that could’ve happened during the experiment that could explain the variation from the expected weight %?
To do this you need the mass of the acetic acid and the mass of the vinegar
you are provided the density of the vinegar. You can use the density for volume-->grams vinegar
Trending now
This is a popular solution!
Step by step
Solved in 6 steps
