Calculate the concentration of an HCl solution if 100.0 mL of the HCl required 33.00 mL of 0.2000 M Mg(OH)2 to reach the titration endpoint. (Use stoichiometry, answer is 0.1320 M) Mg(OH)2 + 2 HCl ® 2 H2O + MgCl2

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Calculate the concentration of an HCl solution if 100.0 mL of the HCl required 33.00 mL of 0.2000 M Mg(OH)2 to reach the titration endpoint. (Use stoichiometry, answer is 0.1320 M) Mg(OH)2 + 2 HCl ® 2 H2O + MgCl2

Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint.
Mg(OH)2 + 2 HCI → 2 H₂O + MgCl₂
There is enough information to calculate the moles of base but not the moles of acid.
mol
a. 0.1000
h. CaCO3(s)
-1
0. H₂PO41
v. H₂CO3
bb. 3.300 x 10-²
hh. 2.16 x 10-6
b. 0.1320
i. OH-1
-2
p. CO32
W. PO4³
-3
L)(-
mol Mg(OH)3)(-
mol HCI
c. HX
j. H30+1
q. HCO3-1
x. HC₂H3O2
dd. 2
jj. 0.2000
d. Al+3
k. SO4
CC. 3
ii. 1.60 x 10-5
-2
r. H₂S
e. CO₂
-) =
y. C₂H30₂-1
ee. 1
I. Mg+2
s. HS-1
mol HCI
mol Mg(OH)2
M HCI
f. CaF2(aq)
m. Cl-1
t. 5-²
z. 1 x 10-14
ff. 0.099536
kk. 6.600 x 10-³
g. HF (aq)
n. HPO4²
u. H₂O(liq)
mol Mg(OH)3
aa. 1.32 x 102
gg. 3.95 x 10-3
mol HCI
Transcribed Image Text:Calculate the concentration of an HCI solution if 100.0 mL of the HCI required 33.00 mL of 0.2000 M Mg(OH)₂ to reach the titration endpoint. Mg(OH)2 + 2 HCI → 2 H₂O + MgCl₂ There is enough information to calculate the moles of base but not the moles of acid. mol a. 0.1000 h. CaCO3(s) -1 0. H₂PO41 v. H₂CO3 bb. 3.300 x 10-² hh. 2.16 x 10-6 b. 0.1320 i. OH-1 -2 p. CO32 W. PO4³ -3 L)(- mol Mg(OH)3)(- mol HCI c. HX j. H30+1 q. HCO3-1 x. HC₂H3O2 dd. 2 jj. 0.2000 d. Al+3 k. SO4 CC. 3 ii. 1.60 x 10-5 -2 r. H₂S e. CO₂ -) = y. C₂H30₂-1 ee. 1 I. Mg+2 s. HS-1 mol HCI mol Mg(OH)2 M HCI f. CaF2(aq) m. Cl-1 t. 5-² z. 1 x 10-14 ff. 0.099536 kk. 6.600 x 10-³ g. HF (aq) n. HPO4² u. H₂O(liq) mol Mg(OH)3 aa. 1.32 x 102 gg. 3.95 x 10-3 mol HCI
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