Molar masses for all compounds in the equation: K: 39.10 g/mol H₂O: 18.02 g/mol KOH:56.11 g/mol H₂: 2.02 g/mol 2K (s) + 2 H₂O (1) 2 KOH (s) + H₂ (8) You need to plan a reaction to produce 20 L of H2. What mass of potassium (K) will you use to accomplish this?

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Chapter1: Chemical Foundations
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Solve like the example attached. Apply the significant figure rule to the final answer. 

Chemistry Vocabulary
WORD WALL
volume-mass stoichiometry
+ 2 50₂ MU
+ O₂ (g)
1. Convent volume of the given chemical to moles of
the given chemical using the molar volume of the
2. Convert moles of the given chemical to moles of
the desired chemical using mole ratio.
3 Convert moles of the desired chemical to mass of
the desired chemical using the molar mass of the
2 Caso, (5)
1.4190
6
BRUNE
1m 50.
F
F
What mass of CaO is required to react
completely with 1.4 L of 50,2
Cao molar mass: 56.08 g/mol
7 md. GO
2 md. 50.
2
IDENT
56.08 € Cal
T
3.5g CaQ
Transcribed Image Text:Chemistry Vocabulary WORD WALL volume-mass stoichiometry + 2 50₂ MU + O₂ (g) 1. Convent volume of the given chemical to moles of the given chemical using the molar volume of the 2. Convert moles of the given chemical to moles of the desired chemical using mole ratio. 3 Convert moles of the desired chemical to mass of the desired chemical using the molar mass of the 2 Caso, (5) 1.4190 6 BRUNE 1m 50. F F What mass of CaO is required to react completely with 1.4 L of 50,2 Cao molar mass: 56.08 g/mol 7 md. GO 2 md. 50. 2 IDENT 56.08 € Cal T 3.5g CaQ
Molar masses for all compounds in the equation:
K: 39.10 g/mol
H₂O: 18.02 g/mol
KOH: 56.11 g/mol
H₂: 2.02 g/mol
2K (s) + 2 H₂O (1)
2 KOH
(s)
+ H₂ (g)
You need to plan a reaction to produce 20 L of H₂. What mass of potassium (K) will you use to accomplish this?
Transcribed Image Text:Molar masses for all compounds in the equation: K: 39.10 g/mol H₂O: 18.02 g/mol KOH: 56.11 g/mol H₂: 2.02 g/mol 2K (s) + 2 H₂O (1) 2 KOH (s) + H₂ (g) You need to plan a reaction to produce 20 L of H₂. What mass of potassium (K) will you use to accomplish this?
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