Molar concentration of NaOH solution:Volume of the original acid sample:Volume of NaOH titrant (at equivalence point):Moles of acid in sample:Molar concentration of acid:Identity of acid (strong or weak):Identified pka of weak acid:Calculated Ka of weak acid:Solution T25.00mL12.10 mL0.09927 M0.0012011M0.04804MStrongPercent error of weak acid pKa (assume pka = 4.75 (acetic acid))4.67Solution 225.00mL12.67mL0.001258M0.05032MWeakpka of weakркаacid.|Note: The acid (strong and weak) react in a 1:1 ratio with the base.On additional paper, clearly show an example of each calculation performed to fill in the report sheet. Ifcalculations are done in your lab notebook, photocopies are acceptable.Include all titration curves with titles, correctly labeled axes, the correct coordinates for the equivalencepoint, where pH = pka (when applicable), and correct volumes/pH values.

The question is based on the concept of titrations. we need to calculate acid dissociation constant…

Molar concentration of NaOH solution: Volume of the original acid sample: Volume of NaOH titrant (at equivalence point): Moles of acid in sample: Molar concentration of acid: Identity of acid (strong or weak): Identified pKa of weak acid: Calculated Ką of weak acid: Solution 1 Tist 25.00mL 12.10mL 0.09927M 0.00/2011 M Strong 0.04804 M Percent error of weak acid pKa (assume pka = 4.75 (acetic acid)) 4.67 Solution 2 25.00mL 12.67mL 0.001258M 0.05032 M Weak pka of weak acid. Note: The acid (strong and weak) react in a 1:1 ratio with the base. On additional paper, clearly show an example of each calculation performed to fill in the report sheet. If calculations are done in your lab notebook, photocopies are acceptable. Include all titration curves with titles, correctly labeled axes, the correct coordinates for the equivalence point, where pH = pK, (when applicable), and correct volumes/pH values.

Molar concentration of NaOH solution: Volume of the original acid sample: Volume of NaOH titrant (at equivalence point): Moles of acid in sample: Molar concentration of acid: Identity of acid (strong or weak): Identified pKa of weak acid: Calculated Ką of weak acid: Solution 1 Tist 25.00mL 12.10mL 0.09927M 0.00/2011 M Strong 0.04804 M Percent error of weak acid pKa (assume pka = 4.75 (acetic acid)) 4.67 Solution 2 25.00mL 12.67mL 0.001258M 0.05032 M Weak pka of weak acid. Note: The acid (strong and weak) react in a 1:1 ratio with the base. On additional paper, clearly show an example of each calculation performed to fill in the report sheet. If calculations are done in your lab notebook, photocopies are acceptable. Include all titration curves with titles, correctly labeled axes, the correct coordinates for the equivalence point, where pH = pK, (when applicable), and correct volumes/pH values.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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