ARUCATIONNSCI 113 Chemistry for EngineersLimiting and Excess ReactantsAssignmentGeneral Direction:1. On a separate sheet, answer the following item below.2. Used the format GRESFA (Given, Required, Equation, Solution, and Final Answer).3. In submission, using cam scanner or take a photo of your output.4. Clear, neat, and portrait scanning of your answers will be part of the grading.By process, 560 g of CH1206 (180.2-) is broken down with 1200 g of O2 (16-)molCH1206O2co2H,0a. Which of the two reactants is the limiting reagent?b. Calculate the mass of CO, formed.MATION

Answered: mol- By process, 560 g of CH1206…

Chemistry

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Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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mol- By process, 560 g of CH1206 (180.2) is broken down with 1200 g of O2 (16-) O2 co, + H,0 а. Which of the two reactants is the limiting reagent? b. Calculate the mass of co, formed.