Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so that during its passage through za large cold room used for storage excess, ice formation can be avoided on the chilling coils in the room. Two suggestions have been offered: (1) Cooling the moist air at constant pressure (2) Compressing the moist air at constant temperature 1. If 60% of the initial water in the entering moist air is to be condensed out, to what temperature should the air in process (1) be cooled? 2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)? Moist Dehumidifie PROCESS air Condensed water Additional information: B log 10 Psat [mm Hg] = A –; Component MW A B T[C] + C Water 18 8.14019 1810.94 244.485
Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so that during its passage through za large cold room used for storage excess, ice formation can be avoided on the chilling coils in the room. Two suggestions have been offered: (1) Cooling the moist air at constant pressure (2) Compressing the moist air at constant temperature 1. If 60% of the initial water in the entering moist air is to be condensed out, to what temperature should the air in process (1) be cooled? 2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)? Moist Dehumidifie PROCESS air Condensed water Additional information: B log 10 Psat [mm Hg] = A –; Component MW A B T[C] + C Water 18 8.14019 1810.94 244.485
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so
Moist
Dehumidified
that during its passage through za large cold room used for storage excess,
ice formation can be avoided on the chilling coils in the room. Two
suggestions have been offered:
(1) Cooling the moist air at constant pressure
(2) Compressing the moist air at constant temperature
1. If 60% of the initial water in the entering moist air is to be condensed
out, to what temperature should the air in process (1) be cooled?
2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)?
PROCESS
air
air
Condensed
water
Additional information:
В
log 10 Psat [mm Hg] = A –
Component
A
В
T[°C] + C
Water
18
8.14019
1810.94
244.485](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F724a14e1-400d-42e0-bda8-cc31820c5b64%2F65c7cde4-f71d-4242-bc3b-6b9cf9eeb419%2Fg6scd0i_processed.png&w=3840&q=75)
Transcribed Image Text:Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so
Moist
Dehumidified
that during its passage through za large cold room used for storage excess,
ice formation can be avoided on the chilling coils in the room. Two
suggestions have been offered:
(1) Cooling the moist air at constant pressure
(2) Compressing the moist air at constant temperature
1. If 60% of the initial water in the entering moist air is to be condensed
out, to what temperature should the air in process (1) be cooled?
2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)?
PROCESS
air
air
Condensed
water
Additional information:
В
log 10 Psat [mm Hg] = A –
Component
A
В
T[°C] + C
Water
18
8.14019
1810.94
244.485
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