Modified True or False: Write True if the solution of the problem is correct. Otherwise, rewrite the solution. I. Using the digits 1, 2, 3 and 5, solve the number of 4-digit numbers that can be formed if: 1. The thousands digit must be 1 and repetition of the digits is allowed. Solution: 1 x 4 x 3 x 2 = 24 numbers 2. The number must be divisible by 2 and repetition is allowed. Solution: 3 x 2 x1x 2 = 12 numbers 3. The number has no repeating digits. Solution: 4 x 3 x 2 ×1 = 24
Modified True or False: Write True if the solution of the problem is correct. Otherwise, rewrite the solution. I. Using the digits 1, 2, 3 and 5, solve the number of 4-digit numbers that can be formed if: 1. The thousands digit must be 1 and repetition of the digits is allowed. Solution: 1 x 4 x 3 x 2 = 24 numbers 2. The number must be divisible by 2 and repetition is allowed. Solution: 3 x 2 x1x 2 = 12 numbers 3. The number has no repeating digits. Solution: 4 x 3 x 2 ×1 = 24
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Transcribed Image Text:Modified True or False: Write True if the solution of the problem is correct.
Otherwise, rewrite the solution.
I. Using the digits 1, 2, 3 and 5, solve the number of 4-digit numbers that can be
formed if:
1. The thousands digit must be 1 and repetition of the digits is allowed.
Solution: 1 x 4 x 3 x 2 = 24 numbers
2. The number must be divisible by 2 and repetition is allowed.
Solution: 3 x 2 x1x 2 = 12 numbers
3. The number has no repeating digits.
Solution: 4 x 3 x 2 ×1 = 24
II. Using the digits 1, 2, 3 and 5, solve the number of 3-digit numbers that can be
formed if:
_ 4. The number is divisible by 5,
Solution: 3 x 2 x1 = 6 numbers
II. The code for a safe is of the form X X XX YYY where X is any number from 0
to 9 and Y represents the letters of the alphabet. Solve the number of possible
cases when:
6. the digits and letters of the alphabet can be repeated, but the code
may not contain a zero or any of the vowels in the alphabet.
Solution: 9 x 9 x9 x 9x 21 x 21 x 21 = 9+ x 213
7. the digits and letters of the alphabet can be repeated, but the digits
may only be prime numbers.
Solution: 4 x 3 x 2 x1x 26 x 25 x 24 = 374,400
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