Modern computer memories use parallel-plate capacitors to store information, and these capacitors are the basic elements of a random-access memory (RAM) chip. Assume one of these capacitors has plates with area L x L with L = 0.21 μm and a plate separation of 10 nm.The usual dielectric found between the plates is composed of SiO₂ and has a dielectric constant close to that of glass. What is the capacitanceof the RAM capacitor when it is filled with SiO₂?F

The Capacitance of the RAM capacitor when it is filled with SiO2 is,C=1.522∗10−18FExplanation:Step…

Answered: Modern computer memories use…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Capacitance Problem 15: The gap between the plates of a parallel-plate capacitor is filled with three equal-thickness layers of mica, paper, and a material of unknown dielectric constant. The area of each plate is 120 cm2 and the capacitor’s gap width is 3.25 mm. The values of the known dielectric constants are Kmica = 6.5 and Kpaper = 3.25. The capacitance is measured and found to be 105 pF. Find the value of the dielectric constant of the unknown material.
The figure shows a parallel-plate capacitor with a plate area A = 6.59 cm2 and plate separation d = 9.98 mm. The left half of the gap is filled with material of dielectric constant K1 = 5.20; the right half is filled with material of dielectric constant K2 = 10.1. What is the %D capacitance? A/2 -A/2 d ber i Units
The capacity of a battery to deliver charge, and thus power, decreases with temperature. The same is not true of capacitors. For sure starts in cold weather, a truck has a 500 F capacitor alongside a battery. The capacitor is charged to the full 13.8 V of the truck's battery. How much energy does the capacitor store? Express your answer with the appropriate units. What is the ratio between the energy density per unit mass of the 9.0 kg capacitor system and the 130,000 J/kg of the truck's battery.
The same voltage is applied between the plates of two different capacitors. When used with capacitor A, this voltage causes the capacitor to store 15 µC of charge and 5.3 x 10-5 J of energy. When used with capacitor B, which has a capacitance of 6.4 µF, this voltage causes the capacitor to store a charge that has a magnitude of qB. Determine 9B.
A researcher builds a parallel-plate capacitor with adjustable spacing between the plates. When the plates are at their initial separation, the capacitance is 6.00 μF. (a) At this capacitance, the capacitor is connected to a 19.00 V battery. After fully charging, how much energy (in µJ) is stored in the capacitor? μJ (b) The battery is then disconnected. Without discharging the capacitor, the researcher then doubles the separation between the plates. At this point, how much energy (in μJ) is stored in the capacitor? µJ (c) Without changing this new separation between the plates, the capacitor is discharged, and then reconnected to the 19.00 V battery. Now, after fully charging, how much energy (in µJ) is stored in the capacitor? μJ
Four capacitors are connected as shown. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking ΔVab = 15.0 V.
Instead of buying a capacitor, you decide to make one. Your capacitor consists of two circular metal plates, each with a radius of 5 cm. The plates are parallel to each other and separated by a distance of 1 mm. You connect a 9-volt battery across the plates. Find the capacitance of the capacitor, the charge on each plate, and the excess number of electrons on the negative plate.
What is the electric charge, in the unit of μC, stored in a capacitor with C = 42 μF if the voltage across the capacitor is 1.6 V
A system of capacitors is shown below. What is the equivalent capacitance of the system if the individual capacitors are: Express the answer in microFarads. For example, if the answer came out to be 4.98 x 10-7 F, this is the same as 49.8 microFarads. You would then answer with numeric value of 4.98. C1 = 6.6 x 10-6 F C2 = 5.9 x 10-6 F C3 = 3.4 x 10-6 F C4 = 4.4 x 10-6 F C5 = 8.1 x 10-6 F
Consider a cylindrical capacitor with inner radius r1 = 8.1 cm, outer radius r2 = 14.3 cm, and length L = 16.7 cm. A dielectric with dielectric constant κ = 53 fills the volume between the two cylinders. The capacitor is connected to a 106.6 V battery and is fully charged. What is the charge on the capacitor? Express your answer in Coulombs to 3 significant figures.
An engineer builds a parallel-plate capacitor with adjustable spacing between the plates. When the plates are at their initial separation, the capacitance is 2.00 uF. (a) At this capacitance, the capacitor is connected to a 20.00 V battery. After fully charging, how much energy (in ) is stored in the capacitor? μJ (b) The battery is then disconnected. Without discharging the capacitor, the engineer then doubles the separation between the plates. At this point, how much energy (in µ3) is stored in the capacitor? p] (c) Without changing this new separation between the plates, the capacitor is discharged, and then reconnected to the 20.00 V battery. Now, after fully charging, how much energy (in p) is stored in the capacitor? p3
A parallel-plate capacitor initially has Quartz between its plates and carries charge ±Q. A different dielectric is then inserted between the plates without changing the charge. If the energy stored in the capacitor decreases to 72% of its initial value, what is the value of x for the new dielectric? K =

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