Modern computer memories use parallel-plate capacitors to store information, and these capacitors are the basic elements of a random-access memory (RAM) chip. Assume one of these capacitors has plates with an area of L xL, where L =1.0 µm (=1.0 ×10-6 m), and a plate separation of d =10 nm (=1.0 ×10-8 m). (a) Find the capacitance of such a capacitor. (b) Calculate the amount of charge that must be placed onto the plates to obtain a potential difference of 5.0 V across the plates. (c) How many electrons does this charge correspond to?

Modern computer memories use parallel-plate capacitors to store information, and these capacitors are the basic elements of a random-access memory (RAM) chip. Assume one of these capacitors has plates with an area of L xL, where L =1.0 µm (=1.0 ×10-6 m), and a plate separation of d =10 nm (=1.0 ×10-8 m). (a) Find the capacitance of such a capacitor. (b) Calculate the amount of charge that must be placed onto the plates to obtain a potential difference of 5.0 V across the plates. (c) How many electrons does this charge correspond to?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Consider the following. (LetC₁ = 8.60 µF and C₂ = 2.60 µF.) 6.00 LF + 9.00 V :C₁ (a) Find the equivalent capacitance of the capacitors in the figure. UF (b) Find the charge on each capacitor. on the right 8.60 µF capacitor on the left 8.60 µF capacitor on the 2.60 µF capacitor on the 6.00 μF capacitor HC UC UC UC (c) Find the potential difference across each capacitor. on the right 8.60 μF capacitor V on the left 8.60 μF capacitor V on the 2.60 μF capacitor on the 6.00 μF capacitor
A 191.0 pF capacitor is charged to a potential difference of 71 V, and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the measured potential difference across the first capacitor drops to 31 V, what is the capacitance (in pF) of this second capacitor? Answer:
Problem 3: Consider a parallel plate capacitor having plates of area 1.65 cm2 that are separated by 0.024 mm of neoprene rubber. You may assume the rubber has a dielectric constant κ = 6.7. Part (a) What is the capacitance in nanofarads? Part (b) What charge, in coulombs, does the capacitor hold when 9.00 V is applied across it?
Find (a) the equivalent capacitance of the capacitors in Figure, (b) the charge on each capacitor, and (c) the potential difference across each capacitor. 6.00 pF 8.00 µF 2.00 μΕ 8.00 µF 9.00 V
You measure the capacitance C1 of a capacitor by doing the following: First connect capacitors C1 and C2 in series to a power supply that provides a voltage V that can be varied. The capacitance of C2 is known to be 3.00 mF. Then vary the applied voltage V, and for each value of V measure the voltage V2 across C2. After plotting your data as V2 versus V, you find that the data fall close to a straight line that has slope 0.650. What is the capacitance C1?
Find (a) the equivalent capacitance of the capacitors in Figure, (b) the charge on each capacitor, and (c) the potential difference across each capacitor. 6.00HF 8.00 pF = 2.00 uF E8.00 uF 9.00 V
A series-parallel combination of capacitors consists of a 4-microfarad capacitor in series with a parallel combination of 6 μF and 8 uF. The whole combination is charged to a potential difference of 1000 V. (a) What energy is stored in each capacitor? (b) What is the voltage across each capacitor?
A l-megabit computer memory chip contains many 60.0 X 10-15-F capacitors. Each capacitor has a plate area of 21.0 X 10-12 m. Determine the plate separation of such a capacitor. (Assume a parallel-plate configuration.) The diameter of an atom is on the order of 10-10 m 1 Å. Express the plate separa- tion in angstroms.
A parallel-plate air capacitor of area A = 10.5 cm2 and plate separation of d = 3.60 mm is charged by a battery to a voltage of 51.0 V. What is the charge on the capacitor?
In the figure a 15 V battery is connected across capacitors of capacitances C₁ = C6 = 4.5 μF and C3 = C5 = 2.0C₂ = 2.0C4 = 5.5 μF. What are (a) the equivalent capacitance Ceq of the capacitors and (b) the charge stored by Ceq? What are (c) V₁ and (d) 9₁ of capacitor 1, (e) V₂ and (f) 92 of capacitor 2, and (g) V3 and (h) 93 of capacitor 3? V C₁ I G₁ C C3 C₂
Two parallel-plate capacitors, 6.2 µF each, are connected in series to a 12 V battery. One of the capacitors is then squeezed so that its plate separation is halved. Because of the squeezing, (a) how much additional charge is transferred to the capacitors by the battery and (b) what is the increase in the sum of the charges: the charge on the positive plate of one capacitor plus the charge on the positive plate of the other capacitor? Give your answers in Coulombs. (a) Number i Units (b) Number Units
A capacitor is constructed from two square, metallic plates of sides ℓ and separation d. Charges +Q and -Q are placed on the plates, and the power supply is then removed. A material of dielectric constant κ is inserted a distance x into the capacitor as shown in the figure below. Assume d is much smaller than x. Suggestion: The system can be considered as two capacitors connected in parallel. (Use the following as necessary: ε0, κ, ℓ, Q, d, and x.) (a) Find the equivalent capacitance of the device.Ceq = (b) Calculate the energy stored in the capacitor.U =