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Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time.

Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What causes the large differences in the first steep decrease in all concentrations due to an increase in volume? Why are they different if the coefficients are the same?

Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time. B. C. D. Concentration (mol L-¹) 0.12 0.10 0.08 0.06 0.04 0.02 X Z Which reaction does the graph represent? XX(g) + Y(g) = 2Z(g) 2X(g) = Y(g) + Z(g) 2X(g) = Y(g) + 3Z(g) X(g) = Y(g) + Z(g) Content Mod 5 Factors that Affect Equilibrium T Time pressure ↓, volume p 2 = x = 1/½/₂24 +2 Syllabus outcomes CH12–5, CH12–12 Bands 5-6 Key D
Transcribed Image Text:Mod 5- Question 4 Three gases X, Y and Z were mixed in a closed container and allowed to reach equilibrium. A change was imposed at time T and the equilibrium was re-established. The concentration of each gas is plotted against time. B. C. D. Concentration (mol L-¹) 0.12 0.10 0.08 0.06 0.04 0.02 X Z Which reaction does the graph represent? XX(g) + Y(g) = 2Z(g) 2X(g) = Y(g) + Z(g) 2X(g) = Y(g) + 3Z(g) X(g) = Y(g) + Z(g) Content Mod 5 Factors that Affect Equilibrium T Time pressure ↓, volume p 2 = x = 1/½/₂24 +2 Syllabus outcomes CH12–5, CH12–12 Bands 5-6 Key D
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