E.g. 1 R 4-C-OH I с E One H+ Formic acid, HCHO2, is a monoprotic acid. In a 0.100 M solution of formic acid, the pH is 2.38 at 25 °C. Calculate K. formate. нсног 0.100M 4.17×10 -xx 0.100-4.17×10 0.100 / ра [H30¹] = 10 = 2.38, 70 -pH -3 - २.३४ -3 = 4.17×10 M H₂0 +4.17×10 tx : нзо : + -3 + = 1.82×10 сня Ø -4 +4-17×10 →x 4.17×10 CHỞ CHO CHCHOI (4.17 × 10-3) (4.17 x 10²³) (0.100-4.17 x 10-3) 1.7389 × 10 -5 0.0958 -3 4.17×10
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this is a question from my acid and bases units its already solved here but i dont understand how my teacher did any of this can you step by step explain each step and how and why it's done so i can understand how to do it.
![E.g. 1
R
4-C-OH
I
с
E
One H+
Formic acid, HCHO2, is a monoprotic acid. In a 0.100 M solution of formic acid, the pH is
2.38 at 25 °C. Calculate K.
formate.
нсног
0.100M
4.17×10
-xx
0.100-4.17×10
0.100 /
ра
[H30¹] = 10
= 2.38,
70
-pH
-3
- २.३४
-3
= 4.17×10 M
H₂0
+4.17×10
tx
:
нзо
:
+
-3
+
= 1.82×10
сня
Ø
-4
+4-17×10
→x
4.17×10
CHỞ CHO
CHCHOI
(4.17 × 10-3) (4.17 x 10²³)
(0.100-4.17 x 10-3)
1.7389 × 10
-5
0.0958
-3
4.17×10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84d3133e-efa9-4642-b55d-83025f18a2db%2Fd85e2acd-62b9-48df-8441-96ef5f458f50%2Fio947y_processed.png&w=3840&q=75)
Step by step
Solved in 4 steps with 4 images
Can you explain the whole ice table i don't understand any of it and why each value is where it is and how you know one side x is positive and the other x is negative and how do you know what to put for the E part of the table explain the whole table please.
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