MO22. Supercavitation is a propulsion technology for undersea vehicles that can greatly increase their speed. It occurs above approximately 50 meters per second, when the pressure drops off sufficiently to allow the water to dissociate into water vapor forming a gas bubble behind the vehicle. When the gas bubble completely encloses the vehicle, supercavitation is said to occur. Eight (n = 8) tests were conducted on a scale model of an undersea vehicle in a towing basin with the average observed speed x 102.2 meters per second. Assume that speed is normally distributed with o = 4 meters per second. Use a = 0.05, test Ho: µ = 100 versus H1 : µ< 100. What is the value of zo (2 decimal places, 0.00) and what can be concluded? Provide all the necessary solutions.

Imagine a diver jumping off a spring board that is 10 feet above the water. The board throws the diver up with an upward velocity of 9 feet per second. That means that if there were no gravity, the diver would keep going up at the rate of 9 feet every second. Fortunately for the diver, there is gravity. Eventually, gravity over comes the force of the diving board and the the diver begins to come down. So over all, the diver is thrown into the air fairly quickly, he slows down until he stops, then begins to come back down (slowly at first, then faster and faster until he hits the water). The height of any object like the diver that is projected into the air can be modeled with the following function: h(t) = -16t^2 + v*t + m In this function: h(t) is the height of the object t seconds after it was thrown into the air. t is the number of seconds after the object was thrown in the air. v is the initial upward velocity (for the diver this was 9 ft per second). m is the initial height of the…

*) Find y as a function of x if y" 11y" + 18y' = 32e*, y(0) = 29, y'(0) = 12, y"(0) = 22. y(x) =